Recent content by SpectraPhy09

F.B.D Of first block (I have shown only the horizontal Forces) f1(max) = μ (1kg)(g) = 0.5 * 10 = 5N F.B.D Of the second Block f2(max) = μ (3kg)(g) = 15N Now the string will become taut and the tension will start acting when f = t = 5N But for 0<f<5N there will be no motion between the 1 kg...

But how can there be a negative Mass density? This same approach is there in my textbook also But I didn't get it

Density of the Sphere = 3M/4πR³ Mass of carved out sphere = density × 4π/3 × R³/8 = M/8 The position of center of mass of The Sphere {M(0) - M/8(R/2)}/M-M/8 -R/14 So total distance between centers of the two bodies is R/14 + 3R = 43R/14 So now I found force between the Mass 7M/8 (left out...

Because we wanted to find the trajectory of the particle Which will be in form of its Y-Coordinate & X-Coordinate You can use this formula also because for this situation when the Body is landing on the same height from where it started We can simply write Y=0 and then Find X(eliminating x=0...

I think the correct ans should be c (i.e C>D>A>B ) but its given d in my textbook( There can be a error also but I'm sure) I think C should have the highest basic strength since Hybridisation of N in this is Sp3 so it has the least electronegativity so it can donate its lone pair easily Then it...

There's a correction My textbook says A & C but my ans was coming A, B & C No, I think b to be correct( Sorry for the typo error)

Yes I got your point here . So if it is pushed downward then it should have an downward acceleration so it will sink, right? This means option C should be correct. Yes, Pressure increases as depth increases . So if pressure increases then force due to the liquid acting on the object should also...

Yes Correct.

I think that ans A might be correct because when the body is pushed some force must be applied so it would have a net upward acceleration and it will come back to its initial position. Plz correct me if I'm wrong. Yes given ans is C. Sorry but I didn't got your explanation about compressibility...

My answer is coming a & c but given ans is a, b & c in my textbook. Plz can someone give mechanism for this reaction? Because my teacher only told that 2° and 1° Amines give the test. So answer should be a & c na but it's wrong :(

Yes, I got the answer now(it should be d) Thanks for Help 😊

I think graph a is correct because So distance would be just flipping the graph from That point where the derivative becomes zero to the point where it intersect X-axis It would look something like this Also by first equation of motion Graph of V vs t would be similar to that in the option...

My answer was coming b but it's given wrong in my textbook. Because if a body is submerged completely in a liquid then buoyancy Force = mg So if the net force is Zero then shouldn't the body remain there? Plz can someone tell where did i went wrong? Also can a body float inside a liquid Because...

No, it should be the same, but in opp direction. Is that correct? Oh! so that graph in which the Velocity is different at the same position is correct. I actually thought that it can't have different velocities at the same position at the same instance but it can happen at two different...

I think Option C should be correct since the body has two velocities in the same position which is not possible. They even didn't show an arrow that could tell it has which velocity at its starting point and at the ending point But the given and in my textbook is Option d ( It can have an error...