- #1

SpectraPhy09

- 25

- 3

- Homework Statement
- Coefficient of friction between all the surfaces in 0.5. Which diagram would describe the friction between the ground and the 2Kg Block when f = t N is applied on the 2kg Block? It is given that the string is not taut initially.(Plz check the the diagram in the image attached). take g= 10m/s^2

- Relevant Equations
- F = ma

F(friction) = μmg

F.B.D Of first block

(I have shown only the horizontal Forces)

f1(max) =

F.B.D Of the second Block

f2(max) =

Now the string will become taut and the tension will start acting when f = t = 5N

But for 0<f<5N there will be no motion between the 1 kg and the 2 kg block so the f2=0

but when f > 5N the string will become taut and the friction the Tension will start will acting now suppose the acceleration of the 1 kg block in left direction is a1 then,

(1)a1 = f - T - f1

and suppose the acceleration od the 2kg block is a2 then,

(2)a2 = f1 - f2 - T

But how will be plot the graph between f2 and t after t=5 since we do not know the T ension neither the acceleration of the block.

Also in the option for 0<t<5 there is different graph that mine.

Plz can someone help me how to solve this problem ahead?

(I have shown only the horizontal Forces)

f1(max) =

**μ**(1kg)(g) = 0.5 * 10 = 5NF.B.D Of the second Block

f2(max) =

**μ**(3kg)(g) = 15NNow the string will become taut and the tension will start acting when f = t = 5N

But for 0<f<5N there will be no motion between the 1 kg and the 2 kg block so the f2=0

but when f > 5N the string will become taut and the friction the Tension will start will acting now suppose the acceleration of the 1 kg block in left direction is a1 then,

(1)a1 = f - T - f1

and suppose the acceleration od the 2kg block is a2 then,

(2)a2 = f1 - f2 - T

But how will be plot the graph between f2 and t after t=5 since we do not know the T ension neither the acceleration of the block.

Also in the option for 0<t<5 there is different graph that mine.

Plz can someone help me how to solve this problem ahead?