Recent content by Stendhal

Homework Statement Is there a more intuitive way of thinking or calculating the transformation between coordinates of a field or any given vector? The E&M book I'm using right now likes to use the vector field ## \vec F\ = \frac {\vec x} {r^3} ## where r is the magnitude of ## \vec x...

Since it it centered at the origin, the integration would be ##\int_-.0002^.0002 ## which I believed could be changed to 2 ##\int_0^.0004## Though that is wrong because the function is odd, not even.Also, since the wire length is so small compared to ##\sqrt 8##, would it be possible to solve...

Homework Statement A long, straight wire lies along the z−axis and carries a 4.20 −A current in the +z−direction. Find the magnetic field (magnitude and direction) produced at the following points by a 0.400 −mm segment of the wire centered at the origin. Homework Equations ## \vec B ## = 2...

I'm still not getting what you're saying there. Whoops, that would change how the question works a lot. My bad, R is suppose to be greater than r.

Homework Statement A spherical capacitor is formed from two concentric, spherical, conducting shells separated by vacuum. The inner sphere has radius r the capacitance is C. What is the outer radius R? Already solved the problem, but I'm more wondering on how to derive the equation that I...

Whoops, alright yeah what I did doesn't work out. I flipped the integral limits, which unless I'm making up some sort of fake math technique, allows us to take out a negative sign. So why doesn't that work out this scenario? I understand physically that you integrate from the initial location...

You forgot a negative sign when you evaluated the integral. $$\int { \frac {zdz} {\sqrt [3] {z^2 + r^2}}}$$ Gives: $$\frac {-1} {\sqrt{z^2 + r^2}}$$ Which, when evaluated at the limits $$ \int_0^{-a}$$ Gives the answer of what you got, just with an extra negative sign to counteract the...

Your work is entirely correct. My mistake was not doing a direct integration instead of indirect, so I lost the $$ \frac {1}{r}$$ I really appreciate your help!

Ah, I see. I completely forgot about the charge of the electron in my post. I was still factoring it into my initial work, but I just didn't write it in, which was sloppy of me. Should be e ∫ E • dL = -ΔV

I do see an error in what I wrote for the original equation. It should be: ∫dE = kQ/(r^2 +x^2)^(3/2) where the limits are from 0 to .325m (distance from starting point to center of ring) which I believe should give the change in potential.

Homework Statement A uniformly charged thin ring has radius 13.0 cm and total charge 21.5 nC . An electron is placed on the ring's axis a distance 32.5 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. Find the speed of...

Ah, yes, thank you. I made a calculator error there. Does everything else seem fine to you?

1. The problem statement, all variables and given/known ddata a.) Assume that a 100W light bulb covers 30cm^2 of area, and covers the surface of the Earth (land and water) with such 100W bulbs. How would the total power output compare with the luminosity of the Sun? Note: L_sun = 10^26W and...

Alright, I guess there was some sort of calculator error that messed me up. Thank you for your help!

Alright so I first calculated π*a*sin(θ)/λ, which I got equal to 2.097 Then I took sin(ANS)/ANS = .4122 .4122^2 = .1699 Since the interference pattern for this problem comes out to approximately 1, the final answer is: I = .17I_0 Is that what you got?