Can you explain to me again, why what I have drawn is not the wavefunction but the probability density? I think it might be the wavefunction.....I am still confused. I think it should be the continuation of exponential decay when the wave emerges from the barrier for E < V and for E > V, I...
Like this?
Also, just wana clarify something, I know I am probably being pedantic but anyways...Is 50 % transmission is the same as R = T = 0.5? Cause the question asks for the probability density sketches for 50% transmission.
I think 50% transmission is the same as R = T = 0.5...
This is the quantum harmonic oscillator where \hat a\dagger and \hat a are the step down and step up (SOMETIMES CALLED LADDER) operators according to your definitions.
Correction: I think you meant to say \hat N = \hat a\dagger \hat a
So would the probability density look like this? The transmitted wave and reflected waves have a reduced amplitude...i.e. they are 1/2 of the original amplitude (incident amplitude). This is the plot of the probability density. Does it make sense?
Looking forward to hearing from you soon...
Consider a Quantum Mechanical particle approaching a barrier (potential) of height V_0 and width a. What will the sketch of the probability density look like if there is a 50% chance of reflection and a 50% chance of transmission? Can you explain why cause after reading Griffith' s Quantum...
How do I plot graphs in LaTeX? Example sin(x) to begin with. :frown:
Also, how do I insert pictures in LaTeX? Example, simple circuit diagrams.
student :confused:
I have done clamping, clipping, half wave rectifier and full wave rectifier circuits. For the diagram, I think it is a cos wave with amplitude 10 V but have no idea why. I am genuinely lost here.
student
Sketch the output voltage as a function of time. The AC voltage source is V_{o}cos(\omega)t with V_{o} = 10V and \omega = 2000rad/sec.
I have posted a diode circuit question in the attachment
Ok, I think it should be a sine curve with a 10 V amplitude but am not too sure about the period...
If i multiple both sides by exp(-ik'x) the LHS gives exp(-ik'x-(x/2a)^2). I' m not sure what to do with this to simplify it further. Do i have to try to complete the square in this exponential now?
Plot distance along x axis versus peak number. calculate the slope using the method of least squares. Plot distance from 0th peak versus peak number. Calculate the slope as before. The ratio of the slopes gives the excitation potential.
There is another method using the current just before...