Recent content by SumDood_

The IF frequency is 90MHz. I changed the op-amp to one that is more suitable. Though, there is still significant attenuation after I pass the differential output through a filter. If I connect VB2 instead of ground, the FFT is much noisier. Not sure if that is worth it. What is a bit confusing...

I have made a few changes and implemented a differential amplifier that seems to be working. Now, I have an issue with passive filtering. I am trying to implement a band-pass filter that is centred around the IF. It seems to be not acting as a band-pass filter but attenuating the output signal...

Oh sorry about the file, here is the correct one. Edit: It seems to be working now, but I am kind of confused. I was using the net label VB2 so that both Q2 and Q3 are biased in the same manner. But I changed VB2 to VB3 and Q3 is still working? Like, didn't I just remove the DC biasing by...

So I have managed to bias correctly, but the IF output from Bv is not expected. Though, the voltages look good to me. Do you see what I am missing? One thing that I would appreciate you expanding on is the RF gain capacitor and why it helps with RF gain.

I have been trying to bias my initial topology using a bias chain. I can't seem to push Q3 VCE. I have been unsuccessful as well when trying to reduce VE through RE1. I'd appreciate any advice in understanding what am I doing wrong. I believe Q1 and Q2 are biased correctly but Q3 isn't.

Thanks for this, I really appreciate it. I kept re-reading your response trying to understand what I am doing wrong. My (incorrect) understanding has been that I need to bias the base of a transistor through a voltage and a resistor, which would then allow me to further use it for applications...

I am using the mixer for the purposes of upconversion. The LO is a signal operating at 400MHz, and the RF signal will operate at 200MHz. From the output results, I am pretty sure I am wrong, and the circuit isn't working correctly. I believe the biasing may be incorrect. Is it valid to use...

Thanks for your detailed response! I will be going through your responses and improve my work where I can. This is actually a class project and the design is, for the most part, on me. The 600MHz frequency is arbitrary. If I manage to implement my designs, I would be demonstrating my work in a...

TL;DR Summary: Struggling to implement a BJT Mixer, which is part of implementing RADAR transmitting at 600MHz in LTspice. I am attempting to implement RADAR in LTspice. At the moment, I am trying to implement the following three blocks that would make up the transmitter of the RADAR: power...

Well, yes. That is what I am trying to find out. How does one determine whether any value of central tendency is appropriate or not for a given sample?

Then, does that mean that the mode becomes a relevant central tendency measure? I would say it isn't because it does not provide much information about the sample. If we already know the probability of each sample being drawn is equal, then what benefit does the mode value provide?

When taking a sample from a uniform distribution, every real number within 0 and 1 has equal probability of being drawn. I would think that there would be no mode, as no 2 values would be the same.

A study on strength properties of high-performance concrete obtained by using super-plasticizers and certain binders recorded the following data on flexural strength (in mega-pascals, MPa) from 28 tests: 6.1, 5.6, 7.1, 7.3, 6.6, 8.0, 6.8, 6.6, 7.6, 6.8, 6.7, 6.6, 6.8, 7.6, 9.3, 8.2, 8.7, 7.7...

$$\left| \frac{V_R}{V_S} \right| ^2 = \frac{R^2}{R^2 - 2R^2 \omega^2 L C + R^2 \omega^4 L^2 C^2 + \omega^2 L^2 }$$ Let's try one more time: \begin{align*} \frac{d}{dC}\left| \frac{V_R}{V_S} \right| ^2 &= \frac{d}{dC}\left(\frac{R^2}{R^2 - 2R^2 \omega^2 L C + R^2 \omega^4 L^2 C^2 + \omega^2 L^2...

@The Electrician I tried this: \begin{align*} V_R &= V_S \cdot \frac{R}{R + \left( j \omega L \right) \left(j \omega R C + 1 \right)} \\ \\ V_R &= R\cdot V_S \cdot \left( R-\omega^2RLC+j\omega L\right)^{-1} \\ \\ \frac {dV_R} {dC} &= -R\cdot V_S \cdot \left( R-\omega^2RLC+j\omega L\right)^{-2}...