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Btw is the answer 566.7 Hz ??

As Chi Meson stated "difference in tube length between any two successive harmonics is half a wavelength", using this u can easily find the wavelength and then u can find velocity. U will find that the lowest frequency for the tube will be in the second harmonic.

Binding energy= (mass of the total no of protons and the nucleus - mass of the atom itself)/c^2.

here u have to take x=0 as u r considering the perpendicular velocity. So once u assume that differentiate it and then u will get the max. value

Here is the correct solution I just figured out. fR=I(alpha) ...(f=frictional force) maR=(2/5)mR^2*(a/R) ( where a is the translational accln.) m(Vx-Vo)=(2/5)mR^2*((Vx-Vo)/R) from here u will get Vx=(5/7)Vo... =p

can u give me a diagram of the arrangement because in I assumed electric field to be in the left directrion and positive charge in the left and the negative charge in the right. Is that right?

Eq=kq^2/(20sin10)^2+Tsin10...1 mg=Tcos10...2 Solving these two equations u should be able to get the answer.

ok distance traveled from the time the ball has been thrown and it starts to roll= (Vo^2-Vx^2)/2a. Vx being the final velocity, a being the accln due to friction. Now I apply the conservation of energy theorem 0.5mVo^2=0.5mVx^2+0.5I(Vx/R)^2+ma(Vo^2-Vx^2)/2a after solving this equation I get...

Homework Statement A battery has an emf=6V. The battery is connected in series with an ammeter and a voltmeter. If a certain resistor is connected in parallel with the voltmeter reading decreases by a factor of 3, and the ammeter reading increases by a factor of 3. What is the INITIAL READING...

i Dont get ur questions properly. What is the distance between the two spheres? is the angle 10degrees from vertical?

I tried to take into account of the friction but I got (sqrt5)/3.

from what I know we use Asin(wt) when u start counting ur time from the equilibrium position while Acos(wt) for time starting from the amplitude of the SHM. U don't need to worry about phase constant here since the system is starting from its mean(equilibrium position).

first of all, I think it should be an inelastic collision. If it is so, Then as u have done above u can find the v of the system. This will be vmax. Hence equate the total kinetic energy of the system with the with the total potential energy 0.5 *k *x^2. The x u will get now is the ampitude. W u...

it is not that the "same spring will have different spring constant", but different length of the same spring will have different spring constant. Suppose u have one string of 1 m and k=1. so if u break it like 2/3 from say right. Then the spring constant of the right spring will be 3k/2 will...

APhO 2004 problem 2. It is similar to this one. Look at the solution there.