Recent content by TaylorHoward21

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    Design of Hydropowered Turbine Propeller for Mobile Charger

    We have already created design specifications, I can try to share it if you would like to see. The weight shall be less than 3lbs and should be less than 1.5lbs. Fixed pitch propeller provides lower weight than others. Printing will be done using PETG as it will outperform PLA and will be more...
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    Design of Hydropowered Turbine Propeller for Mobile Charger

    Locations will be small rivers and creeks most likely. The project is taking the form of a "product" that will have backpackers and outdoor enthusiasts as the target audience. So we are to imagine that the "product" would be utilized as such, in remote outdoor locations. Our goal is to provide...
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    Design of Hydropowered Turbine Propeller for Mobile Charger

    Thanks for the quick reply! Yes, I have done some more simplified research and it seems that most pico/micro hydro turbines are modeled with Kaplan and Francis turbines for stationary projects. My group is going with fixed pitch so we don't overcomplicate the task or go over the budget. There...
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    Design of Hydropowered Turbine Propeller for Mobile Charger

    I am currently working on a project for an undergraduate course in university. My team and I have decided to make a hydropowered mobile device charger, and I am responsible for the design and modeling of the turbine propeller. This turbine will need to be able to function in low velocity streams...
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    Velocity of a slider immediately before impact

    Thank you. I will go back and make sure to include the correct amount of significant figures.
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    Velocity of a slider immediately before impact

    T1 + V1 = T2 + V2 0 + mAgh = 0.5mAV2A1 + 0 40 = (5/32.2)VA2 VA1 = 16.0499 ft/s Edit: Accidentally Used two notations for Kinetic Energy in the "Useful equations" section. Changed it to correctly notate Kinetic and Potential. This notation is used in R.C. Hibbeler Dynamics 14th Ed.
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    Am I setting up this kinematic equation properly?

    So if I change X0 to be = 0 the new answer I get is 1105.5m. This still seems rather far for a car to stop from 66.5m/s to 0m/s. Is -2.00m/s^2 simply just a very slow breaking acceleration?
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    Am I setting up this kinematic equation properly?

    A race car starts from rest and goes a quarter mile (1/4 mi) in 12.1 seconds. Assume the acceleration of the car is constant. (a.) What is the acceleration of the car? (b.) What is the final speed of the car? (c.) If you hit the brakes, how far would it take to stop the car if the breaks cause...
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    Solving Force and Motion: Pulling 25.0 kg Sled 25m

    Yes, you are correct. Here is my diagram: So assuming V0 = 0 I find that time t = 9.4 seconds.
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    Solving Force and Motion: Pulling 25.0 kg Sled 25m

    << Mentor Note -- New poster has been reminded to use the Homework Help Template when posting schoolwork questions >> A 25.0 kg sled is pulled (assume frictionless) with a force of 15.0 N at an angle of 20 degrees above the horizontal. (a.) How long will it take to pull the sled 25m? (b.) How...
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