- #1

- 10

- 1

**A race car starts from rest and goes a quarter mile (1/4 mi) in 12.1 seconds. Assume the acceleration of the car is constant. (a.) What is the acceleration of the car? (b.) What is the final speed of the car? (c.) If you hit the brakes, how far would it take to stop the car if the breaks cause an acceleration of -2.00 m/s**

I believe I have parts a and b right, however I am not confident with my process of solving part C.

^{2}?I believe I have parts a and b right, however I am not confident with my process of solving part C.

**1/4 mi ≈ 402.3 m**

**a.)**acceleration = 5.5m/s^2

**b.)**Final speed (at 12.1 seconds) = 66.5 m/s

c.) For part C, I reset the known values to:

a = -2.00m/s

^{2}

V

_{0}= 66.5m/s

V = 0 (because solving for car stop which is zero velocity)

X

_{0}= 402.3m

The equation I used: v

^{2}- V

^{2}

_{0}= 2a(x - x

_{0})

The answer I got was 1507.8m = x

For a car going 66.5m/s that is slowing down at -2.00 m/s

^{2}does this answer seem practical? I am struggling to check my work here.

Many thanks.