Recent content by thedean515

that's right, thank you very much. I didn't thought about that. My question them become how to differentiate a absolute value or a determinant of a matrix?

Thank you for your help. I tried, but I still can't get |A| from abs(U')*abs(lamda)*abs(U), which I will called it A2. A2- abs(A) = ans = 6.3607 3.6121 1.6572 -1.8534 1.0880 3.6121 3.5874 1.4778 -1.1544 0.8109 1.6572 1.4778 2.1712 -0.4520...

I read from a book and claim that for any hermitian matrix can be diagonalized by a unitary matrix whose columns represent a complete set of its normalized eigenvectors. It then given an equation...

someone can help me

We have two definitions for the autocovariance of finite samples $y\left(t\right)$and it is given as \begin{equation} \hat{r}\left(k\right)=\frac{1}{N-k}\sum_{t=K+1}^{N}y\left(t\right)y^{*}\left(t-k\right),\qquad0\le k\le N-1\end{equation} and \begin{equation}...

Can anyone help me?

part soultion Hi, Just to remind you the calculation for the coaxial cable case. The electric field of an infinite line of charge is given E = \frac{D}{\epsilon_0 \epsilon_r} = \hat{r} \frac{\rho_l}{2 \pi \epsilon_0 \epsilon_r r} in radial direction. V = -\int_a^b Edl =...

Hi, As you know the capacitance per unit length of a standard coaxial cable is C_{coax} = \frac{2 \pi \varepsilon_{0} \varepsilon_{r}}{\ln{\frac{b}{a}}} where b is the radius of the cable and a is radius of the central conductor. . If we only want to know the capacitance of a...

Hi, thanks chistianjb. I was going to using convolution, but seems too much maths involved. Because rectangular has only value within a range, this will simplfy the integration lots. I worked out the range of t is between (T+T^2)/2 and (T^2-T)/2, am I right? sb can try to integrate[Sin[w0...

Homework Statement I'd like to prove a F/T pair and to confim if they are correct. s(t) = A Sin[w0 t] * rect[t/T - T/2] ... (1) it's Fourier transform is S(f) = exp(-j w T)*T/2*A* {Sinc[(w+w0)T/2/Pi] + Sinc[(w-w0)T/2/Pi]} ...(2) where rect is rectangular function Homework...