Recent content by theJorge551

Fantastic, thanks for your help, bacon. :D I've got another problem, which I think I've solved, but the proof seems so utterly simple that I'm skeptical of whether or not I've overlooked some big assumption that I might have made. Could someone tell me if my proof is sufficient (if we take the...

You're correct for the first part; it was a typo. For the second part, you're right -- I made a mistake as to what my point of focus was, so it should be CD x DE = (r-DO) x (r+DO), simplifying to 18 = r^2 - 4, and thus r = sqrt(22). Did I make any other silly errors, or does this match what you...

Thanks for your hint! I did what you suggested, and stated that 36 = BC x BE, And knowing that BC = 2, BE must be 12. Because BD = 6, BE = 6 as well...then I said that there is a diameter through OD intersecting the circle at points F and G (which are both irrelevant, directly, because I can...

I went over the problem today, and it turns out that the wording was fallacious. I've seen the solutions for both of these problems now (the way they were meant to be interpreted) and I no longer need help with them...but the ones in my other thread are much more pressing. :P

Homework Statement Point A is on a circle whose center is O, AB is a tangent to the circle, AB = 6, D is inside of the circle, OD = 2, DB intersects the circle at C, and BC = DC = 3. Find the radius of the circle. Homework Equations Power of a point theorem (several cases found online...

Edited out the weird symbols and replaced them. Should be all clear now. Sorry for the confusion.

Problem: Point P is on arc AB of the circumcircle of regular hexagon ABCDEF. Prove that PD + PE = PA + PB + PC + PF. I'm aware that I'm supposed to use Ptolemy's theorem, which states that I've drawn the hexagon and it seems like an unreasonably long proof is required if I wanted to prove it...

It's easier to integrate x^4 than it is to integrate 1/(x^2+9). Set your u and dv values differently and apply tabular integration once again.

Thanks guys! I'm teaching myself Taylor polynomials and series now. I hope to have grasped the reasoning behind this summation before the end of the two-week session we have to work on this project, so I can put the actual analysis at the end of my report. I find it really pointless to give us...

Maybe I should have been more clear in my original post; I've seen sequences before but I've never done calculations that reduce the value of the sum to a concise little formula. I've seen the proofs for this being done but I've never learned any hard and fast methods of creating one of these...

Homework Statement "Aim: In this task, you will investigate the sum of infinite sequences tn, where tn = {\frac{(x\ln{a})^n}{n!}}, and t0=1 Consider the sequence when x=1 and a=2. Using technology, plot the relation between Sn (the sum of t0+...+tn) and the first n terms of the sequence for...

All right, so on the upper end of x, the limit is 2 (2^2 = 4), and it can go down to -2 before becoming undefined yet again...so the domain of F would be [-2,2].

Because F(x) is independent of the values of t, I think that the domain of F is the set of real numbers. The value of t being constricted to the area between 0 and 4 should have nothing to do with the constriction of x as it varies, correct?

Ahh, thank you for the clarafication, slider. I had a suspicion that the domain of x is the same as the domain of t.

Homework Statement F(x) \ = \ \int\limits_{1}^{x^2}{\frac{10}{2+t^3}} \ dt Where {0}\leq{t}\leq{4}. Find the domain of F. Homework Equations N/A The Attempt at a Solution I'm not quite sure how to tackle this problem. It doesn't seem as though the domain of t has much at all to do with...