Find Domain of F(x): Homework Statement

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Homework Help Overview

The problem involves determining the domain of the function F(x), defined as an integral from 1 to x² of the function 10/(2+t³), with a specified condition for t (0 ≤ t ≤ 4).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the limits of integration and the domain of F(x), questioning how the constraints on t affect the domain of the function. Some express uncertainty about the relevance of the condition on t, while others suggest that it may define the valid range for x.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have offered insights into the implications of the limits on t for the domain of F(x), while others are still seeking clarification on these relationships.

Contextual Notes

There is a noted ambiguity regarding the relationship between the constraints on t and the resulting domain of F(x). Participants are considering how the integral's limits influence the evaluation of F at specific points.

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Homework Statement



F(x) \ = \ \int\limits_{1}^{x^2}{\frac{10}{2+t^3}} \ dt

Where {0}\leq{t}\leq{4}.

Find the domain of F.

Homework Equations



N/A

The Attempt at a Solution



I'm not quite sure how to tackle this problem. It doesn't seem as though the domain of t has much at all to do with the domain of F(x), so could anyone steer me in the correct direction on how to approach this?
 
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Why is there a condition 0 ≤ t ≤ 4? The variable t is only used for the integration and has no bounds.
 
I believe the limits on t define the domain of the function being integrated. That is, the integral is not defined if the limits of the integral venture outside the domain of the internal function.
 
Ahh, thank you for the clarafication, slider. I had a suspicion that the domain of x is the same as the domain of t.
 
The acceptable values for t are not the same as the domain of F (ie, the acceptable values for x). I can't tell from the last comment whether you were saying that you thought that or not.
 
Because F(x) is independent of the values of t, I think that the domain of F is the set of real numbers. The value of t being constricted to the area between 0 and 4 should have nothing to do with the constriction of x as it varies, correct?
 
Well, suppose you want to evaluate F(3). Then you need
\intop_1^9 \frac{10}{2+t^3} dt

But t is supposed to be between 0 and 4, right? So this expression is undefined.
 
All right, so on the upper end of x, the limit is 2 (2^2 = 4), and it can go down to -2 before becoming undefined yet again...so the domain of F would be [-2,2].
 
I agree.
 

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