Homework Statement
S(x(x+1)1/2) dxHomework Equations
The Attempt at a Solution
u=x+1
du=1
x=u-1
S(x(u)1/2) du
S(((u-1)(u)1/2) du
S((u2-u)1/2) du
S(u-u1/2) du
S((1/2)u2-(2/3)u3/2)
=(1/2)(x+1)2-(2/3)(x+1)3/2) + COnline homework says it's wrong... Where did I mess up?
Yeah, I know. :) It's jut that it's worth 15 out of 100 points on our lab and our professor usually makes those questions the most difficult. It's unusual to have one so simple.
Homework Statement
g(x)=ex and the x-axis on the interval [0,ln(9)]
a) Set up definite integral that represents area
b) Find area using fundamental theorem.
Homework Equations
The Attempt at a Solution
g(x)=ex [0,ln(9)]
\int^{ln(9)}_{0}e^x dx
= [eln(9)]-[e0]
= [9]-[1]
= 8...
I did that, but I didn't know how to type it into the forums. So I made it the cosxdx [0,2pi] and solved from there. What do you think of my answer for the area?
Homework Statement
f(x)=cosx and the x-axis on the interval [0,2pi]
A) Set up definite integral that represents area above
B) Find area using the fundamental theorem
Homework Equations
The Attempt at a Solution
cosxdx [0,2pi]
= sinx [0,2pi]
= sin(2pi)-sin(0)
= 0
Area=...
Homework Statement
I have a problem where the graph of the equation is below the x-axis at x=0, crosses the x-axis at x=2, and is above at x=5. To find the area of this would I just split the interval into two parts, find both areas, and then add them? Or would I simply ignore the part of the...
Okay, I kind of guessed my way through it based on my notes and came up with 88/3 or 29.3333_ . Now, the next question asks me to do the same thing, but use the right endpoint graph. Wouldn't the answers be the same?
Homework Statement
Use the left endpoint graph with the given number of
rectangles to approximate the area bounded by the
curve f (x), the x-axis, and the line x = 4.
f(x)=x2+x
Homework Equations
No idea.
The Attempt at a Solution
Once again, not a clue how to start this.
Homework Statement
Evaluate the limit analytically if necessary using L’Hopital’s rule:
lim x->0 (1+x)1/x
Homework Equations
The Attempt at a Solution
Well, I can get the thing equal to 1 if I just plug in zero, so do I need to use L'hopital's? This whole thing is very confusing...