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tjohn101
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Homework Statement
f(x)=cosx and the x-axis on the interval [0,2pi]
A) Set up definite integral that represents area above
B) Find area using the fundamental theorem
Homework Equations
The Attempt at a Solution
cosxdx [0,2pi]
= sinx [0,2pi]
= sin(2pi)-sin(0)
= 0
Area= (cosxdx [0,pi/2]) - (cosxdx [pi/2,3pi/2]) + (cosxdx [3pi/2,2pi])
Area= (sinx [0,pi/2]) - (sinx [pi/2,3pi/2]) + (sinx [3pi/2,2pi])
Area= (1-0) - (-1-1) + (0-1)
Area= (1) -(-2) + (1)
Area= 4 square units.
So... What do you think? Is it right? And what exactly does the question mean by "Set up definite integral that represents area above"?