(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

f(x)=cosx and the x-axis on the interval [0,2pi]

A) Set up definite integral that represents area above

B) Find area using the fundamental theorem

2. Relevant equations

3. The attempt at a solution

cosxdx [0,2pi]

= sinx [0,2pi]

= sin(2pi)-sin(0)

= 0

Area= (cosxdx [0,pi/2]) - (cosxdx [pi/2,3pi/2]) + (cosxdx [3pi/2,2pi])

Area= (sinx [0,pi/2]) - (sinx [pi/2,3pi/2]) + (sinx [3pi/2,2pi])

Area= (1-0) - (-1-1) + (0-1)

Area= (1) -(-2) + (1)

Area= 4 square units.

So.... What do you think? Is it right? And what exactly does the question mean by "Set up definite integral that represents area above"?

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# Homework Help: Area for cosx on interval [0,2pi]

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