1. The problem statement, all variables and given/known data f(x)=cosx and the x-axis on the interval [0,2pi] A) Set up definite integral that represents area above B) Find area using the fundamental theorem 2. Relevant equations 3. The attempt at a solution cosxdx [0,2pi] = sinx [0,2pi] = sin(2pi)-sin(0) = 0 Area= (cosxdx [0,pi/2]) - (cosxdx [pi/2,3pi/2]) + (cosxdx [3pi/2,2pi]) Area= (sinx [0,pi/2]) - (sinx [pi/2,3pi/2]) + (sinx [3pi/2,2pi]) Area= (1-0) - (-1-1) + (0-1) Area= (1) -(-2) + (1) Area= 4 square units. So.... What do you think? Is it right? And what exactly does the question mean by "Set up definite integral that represents area above"?