Find area of e^x on interval [0,ln(9)]

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SUMMARY

The area under the curve of the function g(x) = e^x from the interval [0, ln(9)] is calculated using the definite integral ∫ from 0 to ln(9) of e^x dx. The evaluation of this integral yields an area of 8 square units, derived from the expression [e^(ln(9))] - [e^(0)] = 9 - 1. This straightforward calculation raises questions about the complexity typically expected in similar problems, especially given its weight of 15 out of 100 points in the lab assignment.

PREREQUISITES
  • Understanding of definite integrals
  • Familiarity with the exponential function e^x
  • Knowledge of the Fundamental Theorem of Calculus
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail
  • Practice evaluating definite integrals of exponential functions
  • Explore applications of integrals in calculating areas under curves
  • Investigate common pitfalls in integral calculus problems
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Students studying calculus, particularly those focusing on integral calculus and the evaluation of areas under curves, as well as educators preparing lab assignments in mathematics.

tjohn101
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Homework Statement



g(x)=ex and the x-axis on the interval [0,ln(9)]

a) Set up definite integral that represents area
b) Find area using fundamental theorem.

Homework Equations


The Attempt at a Solution


g(x)=ex [0,ln(9)]
<br /> \int^{ln(9)}_{0}e^x dx<br />
= [eln(9)]-[e0]
= [9]-[1]
= 8 square unitsThere's no way it was that easy... Did I mess up somewhere?
 
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Not all problems have to be hard.
 
Yeah, I know. :) It's jut that it's worth 15 out of 100 points on our lab and our professor usually makes those questions the most difficult. It's unusual to have one so simple.
 
tjohn101 said:
Yeah, I know. :) It's jut that it's worth 15 out of 100 points on our lab and our professor usually makes those questions the most difficult. It's unusual to have one so simple.

Maybe. But I don't see how to interpret it as complicated.
 

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