Recent content by Trizz

Homework Statement Assume Harvard has the following marginal cost equation and acts like a competitive firm: MC = 10X + 100 The aggregate demand for education at the College is: X^D("D" simply stands for demand)= 200 - .5p The demand function above does not account for an additional...

Homework Statement Find the equations for the utility maximizing values for x and y U(x,y) = x^2 + y^2Homework Equations Budget constraint: I = PxX +Pyy L(x,y,\lambda ) x^2 + y^2 + \lambda (I - PxX - PyY) The Attempt at a Solution I got the three partial derivatives and set equal to zero...

thanks guys i got it

ok so something like... change in L = 12m * 1200e-6 * 12 = .1728 cm ohh and its 12 regardless if i work in celsius or kelvin so does that seem better?

Homework Statement A concrete highway is built of slabs 12 m long (20°C). How wide should the expansion cracks be (at 20°C) between the slabs to prevent buckling if the range of temperature is -30°C to +32°C? ________ cm Homework Equations change in L = L original * alpha * change...

Homework Statement Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.2000 kg when weighed in air. (Express your answer as 4.2000 kg plus a positive or negative number.) (4.2000 + ________ ) kg Homework Equations Buoyant force = density x gravity x...

thank you so much

mg(h+x) = 1/2kx^2 so would it be 7820(28.9+x) = 1/2(8*10^4)(x^2) then... 226009 + 7820x = 40000x^2 or... -40000x^2 + 7820x + 226009 = 0 then would x be 2.47?I'm only clarifying because I have one chance left to get it right

I remember now... I did it quadratically. My final set up was 4.00e4 x^2 + 7828 x - 226009

Homework Statement An elevator cable breaks when a 798 kg elevator is 28.9 m above a huge spring (k = 8.00 multiplied by 104 N/m) at the bottom of the shaft. (a) Calculate the work done by gravity on the elevator before it hits the spring. I got 226009 which is right (b) Calculate...

I just noticed that it gives me Pluto's minimum orbital velocity at 3.7 km/s. So would plugging that into the formula above, the area one, give me the area of the aphelion (since it would be going slowest then)? Also, how would I determine the velocity of the perihelion.

I believe this equation may help Area=1/2 x (Distance to sun) x (Current Velocity) x (Time) so would it be (.5)(perihelion dis)(?)(anything) then (,5)(aphelion dis)(?)(anything) I put "?"'s in the velocity spot because I don't know how to find the velocity

Homework Statement I have to prove that A1=A2, or the fact that planets will sweep out equal areas in equal amounts of time. The planet I have to do this for is Pluto. Basically, I need help finding the area it "sweeps out" over any length of time of my choosing. Homework Equations...

Homework Statement sec^2(x) tan^2(x) + sec^2(x) = sec^4(x) Homework Equations sin^2 + cos^2 = 1 1+tan^2 = sec^2 1+cot^2 = csc^2 The Attempt at a Solution First, I changed everything to sin and cos to try and make it clearer. 1/cos^2 * sin^2/cos^2 + 1/cos^2 = sec^4...

Thank you guys for being so kind and giving me your time! I think I can get the rest from here.