Calculating Expansion Cracks Width for Concrete Highway -30°C to +32°C

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Homework Help Overview

The problem involves calculating the required width of expansion cracks in a concrete highway that experiences temperature changes from -30°C to +32°C. The original poster presents a scenario where concrete slabs, each 12 m long at an initial temperature of 20°C, need to be analyzed for potential buckling due to thermal expansion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the change in length due to temperature variations using a specific formula. Some participants question the validity of adding the changes for both expansion and contraction, suggesting that only the maximum expansion should be considered. Others emphasize the importance of using Kelvin for temperature calculations.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's calculations and suggesting alternative approaches. There is a focus on clarifying the assumptions regarding expansion versus contraction and the relevance of temperature units. While some participants express confidence in the revised calculations, there is no explicit consensus on the final approach.

Contextual Notes

Participants note that the original poster's calculations may not account for the overall gap size and emphasize the need for clarity on the maximum temperature change. There is also mention of potential confusion regarding the use of temperature scales in the context of thermal expansion.

Trizz
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Homework Statement



A concrete highway is built of slabs 12 m long (20°C). How wide should the expansion cracks be (at 20°C) between the slabs to prevent buckling if the range of temperature is -30°C to +32°C?

________ cm


Homework Equations



change in L = L original * alpha * change in temp

sorry i don't have symbols and stuff

The Attempt at a Solution



I've tried it one way so far.

Basically, I just found the difference between the higher temp and the highway temp, and solved that as one equation. Then i found the difference between the lower temp and the highway temp, and solved that as one equation. Then i added the two answers.

change in L = 12m * 1200e-6(our teacher gave us this for alpha) * (32-20) = .1728

change in L = 12m * 1200e-6 * (20-(-30)) = .72

then i got .8928 cm


any help?
 
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I don't think you care about how much they shrink as compared to how much the slabs expand. The big ouch comes if the slabs expand and hit each other, while if they shrink then the gap just gets a little bigger. I don't see any constraint on the overall gap size itself. Also, you should be working in Kelvin!
 
It seems like you shouldn't add the two. Just find the largest value (as Mindscrape said we only care about expansion) and that should be how much space you should put between the slabs. So the real problem it seems is finding the maximum value of

|x - 20|

On the range 20 < x \le32
 
ok so something like...

change in L = 12m * 1200e-6 * 12 = .1728 cm

ohh and its 12 regardless if i work in celsius or kelvin

so does that seem better?
 
thanks guys i got it
 
Yeah, for changes in temperature the Kelvin scheme usually doesn't matter, though it did for the contraction equation you worked out because you should have got a negative when you had a positive. Get in the habit of working with Kelvin in thermo. You'll be sorry later if you don't.

Yep, that's good. Technically you should have in inequality in your answer.
 
Mindscrape said:
Yeah, for changes in temperature the Kelvin scheme usually doesn't matter, though it did for the contraction equation you worked out because you should have got a negative when you had a positive. Get in the habit of working with Kelvin in thermo. You'll be sorry later if you don't.

Yep, that's good. Technically you should have in inequality in your answer.

He actually would have gotten a negative delta T but he switched the final and initial temperatures.
 

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