Recent content by UWGGEOL

Thats exactly what i did wrong. I corrected and got .11J/m^3. thanks

I tried that using V=kq/r and put q into E=kq/r^2. I also got E using V=Ed and got about 80000 V/m or N/C both times. I still get around .028 J/m^3 for my answer when i put that into the density formula.

Homework Statement A charged isolated metal sphere of diameter 10cm has a potential of 8000V relative to V=0 at infinity. Calculate the energy density in the electric field near the surface of the sphere Homework Equations u=1/2[tex]\(epsilon x E^2) E=kq/r^2 The Attempt at a...

Yeah I tried that before you told me and it was pretty easy and good to know the way i thought was right. I got -3.10x10^3 N/C because of the direction of the field

Homework Statement Two nonconducting spheres, of r1=3.0cm and r2=2.0cm, are placed of an x-axis. They have surface charge densities of +6.0mC/m2 and +4.0 mC/m2, respectively, on their outside surfaces. The center of sphere r1 is on the origin and the center of sphere r2 is 10 cm away. What is...