Recent content by welcomeblack
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Graduate Finding Function that Vanishes Only When x^mu = y^mu
Hi all, Just doing some hobby physics while I put off working on my research. In one dimension, the function \begin{equation} f(a,b)=[1-\exp(-(a-b)^2)] \end{equation} vanishes when a=b. In Minkowski spacetime though, such a function is not so easy to find (if you require Lorentz invariance). If...- welcomeblack
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- Function Lorentz invariance Minkowski
- Replies: 9
- Forum: Special and General Relativity
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Graduate Another question from Srednicki's QFT book
This thread's a bit old but I'd like to answer this question for people in the future. You're doing fixed-order perturbation theory at order ##\alpha##, which means you drop terms of order ##\alpha^2## You can recognize ##d\alpha / dln \mu## as the beta function, which starts at order...- welcomeblack
- Post #68
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Understanding the Discrepancy in Four-Vector Differentiation in QFT
Ohhh okay I get it. Thanks for your help!- welcomeblack
- Post #3
- Forum: Calculus
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Graduate Is It Called the Random Phase Approximation?
I've seen something similar used in mean field theory to estimate the partition function of some difficult to calculate system. I think the particular step that reminds me of your equation is called the Bogoliubov Inequality.- welcomeblack
- Post #2
- Forum: Calculus
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Graduate Understanding the Discrepancy in Four-Vector Differentiation in QFT
Hi all, I'm working on some QFT and I've run into a stupid problem. I can't figure out why my two methods for evaluating i\gamma^\mu \partial_\mu \exp(-i p \cdot x) don't agree. I'm using the Minkowski metric g_{\mu\nu} = diag(+,-,-,-) and I'm using \partial_\mu =...- welcomeblack
- Thread
- Differentiation
- Replies: 2
- Forum: Calculus
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Graduate Velocity Addition: Solving Minkowski Space with Metric Techniques
jkl71: The time t is just a coordinate on the manifold that every observer can agree on, but is not actually an observable. The proper time \tau is what the observer actually measures, and is different for each observer, so I labelled them with indices according to which observer the proper time...- welcomeblack
- Post #4
- Forum: Special and General Relativity
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Graduate Velocity Addition: Solving Minkowski Space with Metric Techniques
Hi all. I'm taking a course in GR and trying to get my intuition and mathematical techniques up to speed. I've been trying to derive the velocity addition formula in Minkowski space, but for some reason I can't do it. Here's what I have: I'll use the Minkowski metric of signature...- welcomeblack
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- Addition Metric Velocity Velocity addition
- Replies: 6
- Forum: Special and General Relativity
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Graduate Fierz Identity Substitution Into QED Lagrangian
Okay so the spinor components on the LHS are the same as those on the RHS. Avoiding any spinor division (since fzero says it isn't generally well defined), if we take the partial of (psibar*psi)(psibar*psi) with respect to psibar, we get from the LHS \frac{\partial}{\partial\bar{\psi}}...- welcomeblack
- Post #4
- Forum: Quantum Physics
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Graduate Fierz Identity Substitution Into QED Lagrangian
Hi all, I've been playing around with spin 1/2 Lagrangians, and found the very interesting Fierz identities. In particular for the S x S product, (\bar{\chi}\psi)(\bar{\psi}\chi)=\frac{1}{4}(\bar{\chi} \chi)(\bar{\psi} \psi)+\frac{1}{4}(\bar{\chi}\gamma^{\mu}\chi)(\bar{\psi}\gamma_{\mu}...- welcomeblack
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- Identity Lagrangian Qed Substitution
- Replies: 3
- Forum: Quantum Physics
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Graduate Spin-half mass term with symmetry breaking
I've been thinking about chapter 11 of Griffiths' Introduction to Elementary Particles. In section 11.7, he gives the Lagrangian density \mathcal{L}=\frac{1}{2}(\partial_{\mu}\phi)(\partial^{\mu}\phi)+\frac{1}{2}\mu^{2}\phi^{2}-\frac{1}{4}\lambda^{2}\phi^{4} and shows that the minimum...- welcomeblack
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- Mass Symmetry Symmetry breaking Term
- Replies: 3
- Forum: Quantum Physics
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Graduate What Would Happen If We Set Up the Double Slit Experiment Differently?
For my explanation, you need to know some elementary QM. The probability to go from initial state to final state is the probability amplitude squared. This probability amplitude is denoted <f|i>, so P(i→f)=|<f|i>|2. The total probability amplitude is the sum of all indistinguishable paths...- welcomeblack
- Post #34
- Forum: Quantum Physics
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Graduate The root second notation for collider energies
Sweet. Thanks a bunch.- welcomeblack
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate The root second notation for collider energies
Every paper I read about cross-section measurements from colliders has a line saying (for example): ...positron-electron annihilations at \sqrt{s} = 40 GeV are studied... 1) What does this mean? I'm guessing it means that in the CM frame, the energy of each beam is 40 GeV. 2) Why use...- welcomeblack
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- Collider Energies Notation Root
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics