Recent content by Whatupdoc
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Finding t for Parametric Equations
lol ah thanks a lot, i got it- Whatupdoc
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding t for Parametric Equations
Evaluate the line integral \int x^5*z*ds where C is the line segment from (0,3,5) to (4,5,7) so first thing i did was found the parametric equations the parametric equations are: x= 4t y= 3+2t z= 5+2t how do i find out what t is? i totally forgot how to do that and i can't seem to...- Whatupdoc
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- Line
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Volume of the solid enclosed by the paraboloids
Find the volume of the solid enclosed by the paraboloids z= 16(x^2 +y^2) and z=32-16(x^2+y^2) i'm not sure how i would find the x bounds for this triple integral. here's my work: 16x^2+16y^2 = 32-16x^2+16y^2 => simplifies to y = +- sqrt(1-x^2) (the y-bounds) z bounds is already given...- Whatupdoc
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- Solid Volume
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Triple integral - solid tetradhedon
Evaluate the triple integral \int \int \int xy*DV where E is the solid tetrahedon with vertices (0,0,0), (4,0,0),(0,1,0),(0,0,7) first I'm going to find n: AB= <-4,1,0> AC= <-4,0,7> AB X AC = <7,28,4> = n so i get this equation: 7(x-4) + 28y + 4z = 0 => 7x+28y+4z = 28 so the...- Whatupdoc
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- Integral Solid Triple integral
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Find the volume of the ellipsoid
Find the volume of the ellipsoid x^2 + y^2 + 10z^2 = 16 solve for z... z=sqrt((16-x^2-y^2)/(10)) z = sqrt((16-r^2)/10) so to find the volume, my integral looks like this: latex doesn't seem to be working, so this could look messy... 2*int (from 0-2pi)*int(from 0-1)*...- Whatupdoc
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- Ellipsoid Volume
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Calculate the volume of the solid under
Using geometry, calculate the volume of the solid under z = sqrt(9- x^2-y^2) and over the circular disk x^2 + y^2 <= (greater than or equal to sign) 9 how extactly would i do this? i have no clue and don't know where to start- Whatupdoc
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- Solid Volume
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Solid that lies above the square (in the xy-plane)
i don't know what i was thinking, thank you- Whatupdoc
- Post #3
- Forum: Calculus and Beyond Homework Help
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Solid that lies above the square (in the xy-plane)
Consider the solid that lies above the square (in the xy-plane) R= [0,1] X [01] and below the elliptic paraboloid z= 64 -x^2 +4xy -4y^2 Estimate the volume by dividing R into 9 equal squares and choosing the sample points to lie in the midpoints of each square. i'm not sure how you...- Whatupdoc
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- Solid Square Xy-plane
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Master the Chain Rule with These Easy Steps - Check Your Work for Accuracy!
chain rule agian - check my work please w = -xy-5yz+3xz, x = st, y = exp(st), z = t^2 dw/ds(5,-2) = ________________________ here's what i did: dw/ds = dw/dx*dx/ds + dw/dy*dy/ds + dw/dz*dz/ds dw/ds = (3z-y)*(t) + (-x-5z)(exp(st)*t) + (3x-5y)(0) plug in x,y and z... dw/ds =...- Whatupdoc
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- Chain Chain rule Check my work Work
- Replies: 1
- Forum: Introductory Physics Homework Help
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How Do You Evaluate dw/dt at t=0 Using the Chain Rule Results?
yup, thanks a lot- Whatupdoc
- Post #3
- Forum: Introductory Physics Homework Help
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How Do You Evaluate dw/dt at t=0 Using the Chain Rule Results?
Suppose w = x/y + y/z x = exp(t), y=2+sin(5t), and z= 2+cos(7t) A.) Use the chain rule to find dw/dt as a function of x, y, z, and t. Do not rewrite x, y, and z in terms of t, and do not rewrite exp(t) as x. I got this one right, the answer is 1/y*exp(t) +(- x/y^2+1/z)*(5*cos(5t)) +...- Whatupdoc
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- Chain Chain rule
- Replies: 2
- Forum: Introductory Physics Homework Help
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Dimensions of a closed rectangular box
i see that your using the product rule, but since 'y'and 2 is constant, can't you just take them out and just take the derivative of 'x'?- Whatupdoc
- Post #5
- Forum: Introductory Physics Homework Help
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Dimensions of a closed rectangular box
Surface Area of a Rectangular = 2xy + 2yh + 2xh DV = (2y)(dx) + (2h)(dy) + (2x)(dh) (2)(50)(0.2) + (2)(100)(0.2)+(2)(70)(0.2) = 88 which is also wrong, did i miss something agian?- Whatupdoc
- Post #3
- Forum: Introductory Physics Homework Help
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Dimensions of a closed rectangular box
The dimensions of a closed rectangular box are measured as 70 centimeters, 50 centimeters, and 100 centimeters, respectively, with the error in each measurement at most .2 centimeters. Use differentials to estimate the maximum error in calculating the surface area of the box. Answer...- Whatupdoc
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- Box Closed Dimensions Rectangular
- Replies: 5
- Forum: Introductory Physics Homework Help
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Find \frac{dz}{dx} at (0,0,0) for sin (2x+4y+z) = 0
If sin (2x+4y+z) = 0 , find the first partial derivatives \frac{dz}{dx} at the point (0,0,0) A.) \frac{dz}{dx}(0,0,0) = _________________ isnt this saying get the derivative of z, respect to x? I'm just kinda confuse since the variable 'z' is also in the problem. well i got the...- Whatupdoc
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- Derivatives Partial Partial derivatives
- Replies: 1
- Forum: Introductory Physics Homework Help