Recent content by Wm_Davies

That definitely makes sense! Thanks! :)

I am a physics major and unfortunately this semester there is almost no classes that I can take in my major field of study due to not having the proper prerequisites. So I am looking for a course that will keep my math skills honed. I am really interested in taking statistical methods which...

What do you mean by P^Tm? Is T in this sense a transpose or the matrix T? Also what is m? Thank you for all your help so far it has really helped me clear up a lot of things!

Okay, I am at my computer so just to make sure we both understand each other... P = \begin{pmatrix} 1 & -1 & -1 \\ 1 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix} D = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix} Since P-1TP=D So then PDP-1=T Then T =...

Okay so if T is an othogonal projection onto W then the eigen values for {v1, v2} must be 1 then right? And if n is orthogonal to W then T*(n) should be equal to zero right? That would make the eigenvalue for n equal to zero. So to find the standard matrix of T I could set P=[n,v1,v2]...

Homework Statement I am part way done with this problem... I don't know how to solve part e or part f. Any help or clues would be greatly appreciated. I have been trying to figure this out for a couple days now. W={<x,y,z>, x+y+z=0} is a plane and T is the orthogonal projection on it. a)...

Thank you Dick. That actually makes a lot of sense! I was just making the problem too hard (as usual).

Homework Statement Find the parametric form for the tangent line to the graph of y=2x2−5x+3 at x=2 is Homework Equations I have no clue! The Attempt at a Solution I found the tangent line to be y=3x-5 I know that the answer has to be in the form... <x0,y0>+t<x1-x0,y1-y0> I...

Yes I get -1.25897 radians when I solve for \omega t + \phi

For \phi I got approximately... 0.240112 radians

x=x_{m}cos(\omega t + \phi) v=-\omega x_{m}sin(\omega t + \phi) So I divided these two functions which gave me the result of... \omega t + \phi = tan^{-1}(\frac{v}{-x \omega}) Since this is equal to all of the stuff in the position function and the velocity function I put it into the...

Yes the formula for velocity was wrong. I divided the two which is how I got \phi is inverse tangen times v divided by the quantity of position times the angular frequency. I must be doing something right because I am able to solve for the amplitude of the function, but I cannot get the position...

Homework Statement I am having a hard time solving this problem and this is my last chance to solve it before it is due and I have to do this for a test tomorrow. A simple harmonic oscillator consists of a block of mass 3.90 kg attached to a spring of spring constant 330 N/m. When t = 0.570...

You can use the equation of change in theta is equal to (1/2)(wfinal+winitial) times the change in time. Since we know the data at the initial point we can plug in the numbers which would be 20(2pi)=(1/2)(wfinal+[(20*2pi)/5])(5) then solve for wfinal

The angular velocity is equal to the change in theta divided by the change in time. You know that there is 20 revolutions on 5 seconds. Angular velocity is measured in radians per second so you must multiply 20(2pi) then divide by the time interval of 5 seconds. This will give you your initial...