Recent content by zaddyzad

I also tried... 60-2I2-4I2=0, 60-2I1-4I3=0, 110 -2I4-2I1=0

Homework Statement http://imgur.com/PJVmXEc Calculate the power delivered to (or dissipated by) R1 Homework Equations V=IR P=I^2R The Attempt at a Solution I attempted to calculate the equivalence resistance by doing... 2+(2^-1+4^-1+4^-1)^-1 = and I get 3. I later...

But gravity is doing work against the cyclist no... ? Its pulling him backwards as he tries cycling upwards.

So I'm thinking mgh = Work done by cyclist - Work done by gravity, and when it asks work done against gravity I'm assuming its asking for the work done by the cyclist. I need wording clarification.

By sliding force I mean the component of gravity opposing motion.

Homework Statement (III) A cyclist intends to cycle up a 7.50° hill whose vertical height is 125 m. The pedals turn in a circle of diameter 36.0 cm. Assuming the mass of bicycle plus person is 75.0 kg, (a) calculate how much work must be done against gravity. The Attempt at a...

opposing the force pointing to the centre

Sorry not sliding force, but instead the force that points to the centre of the circle.

Homework Statement A curve of radius 78 m is banked for a design speed of If the coefficient of static friction is 0.30 (wet pavement), at what range of speeds can a car safely make the curve? Homework Equations The Attempt at a Solution I calculated theta being 36.1...

I'm confused if I could calculate the correct vertical force with my "incorrect" triangle, why wouldn't it allow me to compute the correct parallel force?

Ok, now that I got that. This now leaves me with the some new questions. What was wrong with my vector sum diagram, I still had a component of force parallel to the plane? And how did I get the right answer for by when I solved for the perpendicular force on the plane to be (1.3g + 425tan28) *...

I don't see what you're saying.

h is what I solved for, and it is the force parallel to the direction of motion. I don't see my mistake anywhere..

425 N is the horizontal force parallel to the base of the incline.

http://imgur.com/hBSSssV, I don't see where my mistake is.