Simple Circuits: Calculating Power in a Complex Circuit

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SUMMARY

The discussion focuses on calculating the power delivered to resistor R1 in a complex circuit using Kirchhoff's Laws. The user initially attempted to find the equivalent resistance and calculated a current of 36.67 Amps, resulting in a power dissipation of 2688 watts. However, the calculations were incorrect due to improper application of series and parallel circuit analysis. The correct approach involves using Kirchhoff's Laws for a comprehensive analysis of the circuit.

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Homework Statement



http://imgur.com/PJVmXEc

Calculate the power delivered to (or dissipated by) R1

Homework Equations



V=IR
P=I^2R

The Attempt at a Solution



I attempted to calculate the equivalence resistance by doing... 2+(2^-1+4^-1+4^-1)^-1 = and I get 3.

I later calculate a current of 36.67Amps, and a power of 2688 watts. What did I do wrong.

then I tr
 
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I also tried... 60-2I2-4I2=0, 60-2I1-4I3=0, 110 -2I4-2I1=0
 
zaddyzad said:

Homework Statement



http://imgur.com/PJVmXEc

Calculate the power delivered to (or dissipated by) R1

Homework Equations



V=IR
P=I^2R

The Attempt at a Solution



I attempted to calculate the equivalence resistance by doing... 2+(2^-1+4^-1+4^-1)^-1 = and I get 3.

I later calculate a current of 36.67Amps, and a power of 2688 watts. What did I do wrong.

then I tr

attachment.php?attachmentid=66801&stc=1&d=1392865179.png


(Posting the image makes it more likely that someone will reply to your question.)


This cannot be analyzed as a parallel/series circuit. That sort of method can only be used to replace R2 & R3 by considering them to be in parallel (for this circuit.)

Use Kirchhoff's Laws for the complete analysis.
 

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