I Can (ordo) Fermions convert to Bosons?

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Fermions cannot convert into bosons in a vacuum due to conservation laws, which include energy and momentum. However, interactions involving multiple particles can lead to transformations, such as an electron and positron annihilating to form photons. The discussion highlights that while photons can be compressed and share quantum states, fermions are restricted by the Pauli exclusion principle. The term "compressible" is debated, with the focus on the ability of bosons to form Bose-Einstein condensates, a phenomenon not possible for fermions. Overall, the conversion between these particle types is complex and constrained by fundamental quantum principles.
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TL;DR
Fermions to Bosons
Can Fermions turn into Bosons and thus share the same quantum state and become compressible?

And/Or is the opposite also possible?
 
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An electron and a positron meet and become two photons. The system quantum state is conserved and photons are compressible. The reverse process is possible.
 
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anuttarasammyak said:
An electron and a positron meet and become two photons. The system quantum state is conserved and photons are compressible. The reverse process is possible.
Can you explain what you mean by "(t)he system quantum state is conserved" and in what sense "photons are compressible"?
 
At least energy, momentum, angular momentum of the system is conserved. I hesitate to refer spin or helicity or other pure quantum states due to my poor understanding.
We can change volume of photon gas. On the other hand, I hesitate to say that electron gas is incompressible.
 
RobbyQ said:
TL;DR: Fermions to Bosons

Can Fermions turn into Bosons and thus share the same quantum state and become compressible?

And/Or is the opposite also possible?
A single fermion in vacuum cannot turn into a single boson in vacuum due to conservation laws (can you tell which?). If you want to consider more than one particle please develop.
 
RobbyQ said:
share the same quantum state and become compressible?
"Compressible" is a poor term. The key thing that a system of bosons can do that a system of fermions can't is to form a Bose-Einstein condensate.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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