Sinusoidal Graph - sub intervals

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Homework Help Overview

The discussion revolves around understanding how to find key points or sub intervals for the sinusoidal function Y = 3 sin(4x). The original poster identifies the amplitude and period but struggles with determining the specific points within the interval [0, pi/2] that correspond to the function's behavior.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the general properties of sine functions and how they relate to amplitude and period. The original poster questions how to derive the specific sub points within the defined interval, while others attempt to clarify the relationship between the period and the midpoints of the graph.

Discussion Status

The discussion includes attempts to clarify the process of finding key points on the sine graph. Some participants provide insights into the general behavior of sine functions, while the original poster expresses confusion about applying these concepts to a function with a different period. There is an acknowledgment of understanding from the original poster after receiving input.

Contextual Notes

The original poster references a textbook that suggests dividing the interval into four sub intervals, which raises questions about how to accurately label these points based on the function's period.

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Homework Statement



I can find the graphs amp and period. The only problem is finding the sub points or sub intervals. Say...

Y = 3 sin (4x)
Amp = 3
Period = 2pi/4 = pi/2

But.. don't know how to get the key points of the sub interval. The textbook says I have to divide interval [0, pi/2] into four sub intervals Each of length pi/2 divided by 4. Then they got (0,0), (pi/8, 3), (pi/4, 0), (3pi/8, -3), (pi/2, 0) I don't understand how they got these. Thanks


Homework Equations





The Attempt at a Solution

 
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Draw the base graph y=sin(x) with 0\leq x\leq 2\pi, It has a value of 0 at x=0,\pi,2\pi and a value of 1 and -1 at x=\pi/2, 3\pi/2 respectively.
Basically, every sine graph of the form y=Asin(Bx) will still have this same shape, but the amplitude (A) and period (B) will be different from the base graph y=sin(x).

What you should take away from this is that if the period of sin(x) is 2\pi, then in between the two ends of the period 0 and 2\pi which is \pi, it will also be 0, and in between 0 and its half way mark which is \pi we get the value of its amplitude (in this case 1), and between the half way mark and the end, \pi and 2\pi we get the negative of its amplitude, -1.
 
Mentallic said:
Draw the base graph y=sin(x) with 0\leq x\leq 2\pi, It has a value of 0 at x=0,\pi,2\pi and a value of 1 and -1 at x=\pi/2, 3\pi/2 respectively.
Basically, every sine graph of the form y=Asin(Bx) will still have this same shape, but the amplitude (A) and period (B) will be different from the base graph y=sin(x).

What you should take away from this is that if the period of sin(x) is 2\pi, then in between the two ends of the period 0 and 2\pi which is \pi, it will also be 0, and in between 0 and its half way mark which is \pi we get the value of its amplitude (in this case 1), and between the half way mark and the end, \pi and 2\pi we get the negative of its amplitude, -1.

Thanks, I know that but I don't know how to get the points in between the sin graph

I know if period = 2 pi then the middle point would me pi, but what if it has a different period. I don't know what to label on the graph on the middle part.
 
Last edited:
If the period is 2\pi then middle is half of that \frac{2\pi}{2}=\pi. If the period is some number x then the middle is x/2.
 
Ahhh I see now. Thank you my friend.
 
Good luck! :smile:
 

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