How Do You Balance Zinc and Nitrate in a Basic Solution?

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SUMMARY

The discussion focuses on balancing the chemical equation involving zinc and nitrate ions in a basic solution. The correct coefficients for the balanced equation are 3 for nitrate ions and 2 for zinc, leading to the final balanced equation: 3 NO3-(aq) + 2 Zn(s) --> 2 Zn2+(aq) + 3 NO(g). The participant initially struggled with the oxidation states and mistakenly labeled hydrogen as a negative ion in the reduction reaction, which was identified as the source of confusion.

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  • Understanding of basic chemical equations and stoichiometry
  • Knowledge of oxidation and reduction reactions
  • Familiarity with balancing chemical equations in basic solutions
  • Concept of half-reactions in redox chemistry
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  • Study the principles of balancing redox reactions in basic solutions
  • Learn about oxidation states and how to identify them in chemical reactions
  • Explore half-reaction methods for balancing complex chemical equations
  • Review the properties and reactions of zinc and nitrate ions in aqueous solutions
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Chemistry students, educators, and anyone interested in mastering redox reactions and balancing equations in basic solutions.

KingNothing
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I don't understand this question in my chemistry book. It's not homework, I'm just studying, but I would really like to know.

What are the coefficients in front of nitrate ion and zinc when the following equation is balanced in a basic solution:

___ NO3-(aq) + ___ Zn(s) --> ___ Zn2+(aq) + ___ NO(g)?

1) 2, 5
2) 2, 3
3) 3, 4
4) 3, 2

That's the nitrate ion, zinc, zinc with a 2+ charge, and NO. Can someone explain how to do this? Also, what is the answer, so I can work backwards?

So far, it looks to me like both reactants are being oxidised, so I'm left with a big half-reaction with electrons.
 
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Alright, I finally got it! As it turns out, my error the whole time was labeling H as a negative ion in my reduction reaction.
 

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