Relating the Reynolds number to the Drag Coeffient

Click For Summary
The discussion focuses on the relationship between the Reynolds number (Re) and the drag coefficient (Cd), emphasizing that Cd must be determined experimentally for different velocities. It highlights that Re is influenced by velocity, density, characteristic length, and viscosity, but does not directly include drag force. Participants explore the mathematical connection between Re and Cd, noting that drag force typically relates to the square of velocity (v^2). Concerns are raised about calculations involving high viscosity mediums, like seawater, and the appropriate use of velocity terms in equations. Overall, the conversation underscores the complexity of relating Re to Cd in practical applications.
Noone1982
Messages
82
Reaction score
0
How does one relate the Reynolds number to the Drag Coeffient?

It seems the drag coefficient for different velocities must be determined experimentally per set. I know the Reynolds number is a method to determine laminar or turbulent flow, but can it be used to determine the drag coefficient?
 
Physics news on Phys.org
See discussion on drag coeffient and the relationship between drag force and velocity here.
http://www.grc.nasa.gov/WWW/K-12/airplane/dragco.html

In addition, Reynolds number is a function of velocity, and density, characteristic dimension (length), and viscosity.

One can relate Re and Cd through velocity.
 
Thank you for your response.

The Drag coefficient is given by,

\mbox{C}d\; =\; \frac{1}{2}\mbox{C}d\left( v \right)Apv^{2}

And the Reynolds number is given by,

\mbox{Re}\; =\; \frac{vpl}{\mu }

I'm failing to see how to solve Cd in terms of the Reynolds number since the Reynolds number doesn't contain a drag force.
 
Anyone? The clock is ticking :(
 
Taking Re\, =\, \frac{\rho vl}{\mu }, then

Re^2\, =\, \frac{(\rho vl)^2}{\mu^2 }, or

Re^2(\frac{\mu}{l})^2\, =\,(\rho v)^2}

The one looks at Cd

C_d\; =\; \frac{1}{2}C_d\left( v \right)A\frac{(\rho v)^{2}}{\rho}

then do appropriate substitution.
 
Does it matter if the medium has a very high viscosity? We were looking at a calculation in sea water with a Poise of 1.025. Some gents said that the calculation that we used should use v2 instead of v. What do the gurus think?
 
Unless you have some special kind of Cd, the drag force is usually proportional to v^2 rather than v. Without knowing what specific calculation you are talking about, deponent further sayeth not.
 

Similar threads

Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
2K