Relating the Reynolds number to the Drag Coeffient

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Noone1982
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How does one relate the Reynolds number to the Drag Coeffient?

It seems the drag coefficient for different velocities must be determined experimentally per set. I know the Reynolds number is a method to determine laminar or turbulent flow, but can it be used to determine the drag coefficient?
 
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Thank you for your response.

The Drag coefficient is given by,

[tex]\mbox{C}d\; =\; \frac{1}{2}\mbox{C}d\left( v \right)Apv^{2}[/tex]

And the Reynolds number is given by,

[tex]\mbox{Re}\; =\; \frac{vpl}{\mu }[/tex]

I'm failing to see how to solve Cd in terms of the Reynolds number since the Reynolds number doesn't contain a drag force.
 
Anyone? The clock is ticking :(
 
Taking [tex]Re\, =\, \frac{\rho vl}{\mu }[/tex], then

[tex]Re^2\, =\, \frac{(\rho vl)^2}{\mu^2 }[/tex], or

[tex]Re^2(\frac{\mu}{l})^2\, =\,(\rho v)^2}[/tex]

The one looks at Cd

[tex]C_d\; =\; \frac{1}{2}C_d\left( v \right)A\frac{(\rho v)^{2}}{\rho}[/tex]

then do appropriate substitution.
 
Does it matter if the medium has a very high viscosity? We were looking at a calculation in sea water with a Poise of 1.025. Some gents said that the calculation that we used should use v2 instead of v. What do the gurus think?