Quantum Physics - Calculating Commutators

Click For Summary
SUMMARY

The discussion focuses on calculating commutators in quantum physics, specifically [x, Lx], [y, Lx], [z, Lx], [x, Ly], [y, Ly], and [z, Ly]. Participants highlight the lack of mathematical detail in the source material and suggest applying operators to known eigenfunctions to determine relationships between them. A follow-up question involves repeating the calculations with momentum operators, specifically px, py, and pz. The consensus indicates that commutators involving the same variable and angular momentum operators should yield zero.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with commutator notation in quantum physics
  • Knowledge of angular momentum operators
  • Basic concepts of eigenfunctions and eigenvalues
NEXT STEPS
  • Study the properties of quantum mechanical commutators
  • Learn about angular momentum operator eigenfunctions
  • Explore the implications of commutation relations in quantum mechanics
  • Investigate the role of momentum operators in quantum systems
USEFUL FOR

Students of quantum physics, researchers in theoretical physics, and anyone interested in the mathematical foundations of quantum mechanics.

Bmmarsh
Messages
4
Reaction score
0
Quantum Physics -- Calculating Commutators

The problem states:
Calculate the commutators [x,Lx], [y,Lx], [z, Lx], [x, Ly], [y, Ly], [z, Ly]. Do you see a pattern that will allow you to state the commutators of x, y, z with Lz?

Unfortunately, the book that is asking this question is very vague and doesn't go into any of the math involved. Any help pointing me in the right direction would be greatly appreciated.

[Followup Question]:
Repeat the calculation with x,... replaced by px,...

Again, any help would be amazing!
Thanks!
 
Physics news on Phys.org
I'll try it out

Thanks for your help!
From what you said, I assume that the commutators [x, Lx], [z, Lz], and [y, Ly] should be zero. I'll have to go to my TA to get help with the eigenfunctions of the angular momentum. I missed a week of classes, so I'm just trying to catch up =)

Thanks again.
 

Similar threads

Replies
11
Views
2K
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
800
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K