randa177
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Can we draw an infinite equlateral triangle on a negatively curved surface?
The discussion revolves around the concept of drawing an infinite equilateral triangle on a negatively curved surface, specifically exploring the implications within hyperbolic geometry and the properties of such triangles.
Participants express differing views on the properties of negatively curved surfaces, particularly regarding area and angle measures in triangles. There is no consensus on these points, and the discussion remains unresolved.
Participants mention the dependence of triangle properties on the size and curvature of the surface, indicating that assumptions about area and angles may vary based on the specific context of the discussion.
randa177 said:Can we draw an infinite equlateral triangle on a negatively curved surface?
randa177 said:Actually what confuses me is that the negativle curved surfaces have always a finite toatal area, so how would it be posible to draw an infinite triangle on it? ( we run out of space! )
randa177 said:Actually what confuses me is that the negativle curved surfaces have always a finite toatal area, so how would it be posible to draw an infinite triangle on it? ( we run out of space! )
No. surfaces of positive constant curvature (spheres) have finite area, not sufaces of negative curvature.randa177 said:Actually what confuses me is that the negativle curved surfaces have always a finite toatal area, so how would it be posible to draw an infinite triangle on it? ( we run out of space! )
HallsofIvy said:In either hyperbolic or ellipitic geometry (positive or negative curvature) the angle sum in a triangle depends upon the size of the triangle. Thus, while it can be proven that the three angles in an equilateral triangle are the same, what they are depends upon the size of the triangle. As tiny tim said, the measure of the angles of an "infinitely large" equilateral triangle are 0. The measure of the angles of an "infinitesmally small" triangle are "infinitesmally" close to 60 degrees or \pi/3 radians.
DeaconJohn said:"What won't they think of next?"
tiny-tim said:anabolic geometry!