QFT: Is a^+_{-p}\ a_{-p} = a^+_{p}\ a_{p}?

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SUMMARY

The forum discussion centers on the equality of creation and annihilation operators in quantum field theory, specifically whether \( a^+_{-p} a_{-p} = a^+_{p} a_{p} \) as stated in Peskin's "Introduction to Quantum Field Theory," equation 2.31. The user seeks confirmation of this equality to derive the Hamiltonian expression. The discussion suggests that rewriting the operators in terms of the scalar fields \( \phi \) and \( \pi \) could provide clarity on their relationship.

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ananya J
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Homework Statement


Hi
I was trying to get the expression for H ,eqn 2.31 on page 21 peskins introductory QFT

Homework Equations


I get the final expression only if a^+_{-p}\ a_{-p} = a^+_{p}\ a_{p}
so pls tell me if a^+_{-p}\ a_{-p} = a^+_{p}\ a_{p}
(+ stands for dagger) thanks in advance
 
Last edited:
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don't you think it is a good exercise to rewrite the creation/annihilation operators in terms of phi and pi fields and then find out the relation for yourself? ;-)
 
twas.:smile:
 

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