I found a lepton mass ratio formula:

Click For Summary

Discussion Overview

The discussion revolves around a formula relating the mass ratios of leptons, specifically the electron, muon, and tau lepton. Participants explore the implications of this formula, its accuracy, and its potential connections to other particle masses, including quarks and neutrinos.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a formula involving the natural logarithm of the mass ratios of the muon and electron, noting its accuracy and lack of theoretical backing.
  • Another participant expresses interest in the topic and seeks clarification on the symbols used for the masses.
  • A participant clarifies that the formula relates to the masses of the electron, muon, and tau lepton, providing specific values and accuracy metrics for the ratios.
  • There is a query about the relevance of neutrino mass ratios in this context.
  • A participant mentions the historical belief that neutrinos had no mass and provides upper limits for their masses.
  • Another participant suggests a potential connection of the formula to quark masses, proposing a modification of the constants involved.
  • A suggestion is made to sum the quark masses to see if they equal the proton mass, which is met with skepticism regarding the necessity to account for energy contributions from force carriers.

Areas of Agreement / Disagreement

Participants express interest in the formula and its implications, but there is no consensus on its applicability to quarks or neutrinos, and the discussion remains unresolved regarding these connections.

Contextual Notes

Participants acknowledge limitations in knowledge about neutrino masses and the complexities involved in relating quark masses to proton mass, indicating that assumptions and definitions may affect the discussion.

Hans de Vries
Science Advisor
Gold Member
Messages
1,094
Reaction score
31
I found the following (for what it’s worth):

ln(mu/me) / (2pi-3/pi) = 1.000627
ln(mt/me) / (3pi-4/pi) = 1.00031

me = 0.51099892 MeV (+/-0.00000004)
mu = 105.658369 MeV (+/-0.000009)
mt = 1776.99000 MeV (+0.29 -0.26)

I've not seen it before. There's no theory behind it.
I was trying one, made a bug and stumbled on it.

Regards, Hans
 
Physics news on Phys.org
Nice. I'm really into Leptons. I like this post. :biggrin:

What exactly do you mean by me, mu, and mt?

Do you mean \nu_e, \nu_\mu, and \nu_\tau for electron neutrino, muon neutrino, and tau neutrino respectively?
 
It relates the masses of the electron, the muon and the tau lepton.

ln(mu/me) is the natural logarithm of the ratio between the muon mass
and the electron mass. The value 2pi-3/pi describes it with an accuracy
of 0.06% The other one is twice as exact.

Regards, Hans de Vries
 
Anything with neutrinos and their mass ratios?
 
Unfortunately. there's not enough know about the neutriono masses.
For decades (until recently) it was believed that they had no mass at all.
This is what is known about the upper mass limits:

ve Mass < 3 eV
vu mass < 0.19 MeV
vt mass < 18.2 MeV


Regards, Hans
 
There's more here:

http://www.chip-architect.com/news/2004_07_27_The_Electron.html

Regards, Hans
 
Last edited by a moderator:
it is really intriguing.
I wonder if it applies to quarks to, perhaps changing -1/pi -> +1/pi, or directly.
 
For even more fun, try adding up the quark mass and see if it equals the proton mass.
 
Chronos, for sure it does not. You must account also the energy of force carriers, which form a glueball.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
14K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
12K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
28K