What Are the Key Differences Between Schmidt Decomposition and SVD?

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SUMMARY

The key differences between Schmidt Decomposition and Singular Value Decomposition (SVD) lie in their applications and mathematical formulations. Schmidt Decomposition is specifically used in quantum mechanics to express bipartite quantum states, while SVD is a linear algebra technique applicable to any matrix for dimensionality reduction. The discussion highlights the use of Schmidt Decomposition for states like |\psi>_{AB} = const( |0>_A|0>_B + |1>_A|1>_B) + const( |0>_A|1>_B + |1>_A|0>_B), emphasizing its relevance in quantum state analysis.

PREREQUISITES
  • Understanding of quantum mechanics and bipartite states
  • Familiarity with linear algebra concepts, particularly matrix decomposition
  • Knowledge of Schmidt Decomposition and its mathematical formulation
  • Basic understanding of Singular Value Decomposition (SVD) and its applications
NEXT STEPS
  • Study the mathematical formulation of Schmidt Decomposition in quantum mechanics
  • Explore the applications of Singular Value Decomposition (SVD) in data science
  • Learn about the implications of quantum entanglement in bipartite states
  • Investigate the relationship between Schmidt Decomposition and quantum information theory
USEFUL FOR

Quantum physicists, data scientists, and students studying linear algebra and quantum mechanics will benefit from this discussion, particularly those interested in the mathematical foundations of quantum state analysis.

Nusc
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What's the difference between Schmidt and Single valued decomposition?

https://www.physicsforums.com/showthread.php?t=323859

How could I find it for

<br /> <br /> |\psi&gt;_{AB} = const( |0&gt;_A|0&gt;_B+ |1&gt;_A|1&gt;_B) + const( |0&gt;_A|1&gt;_B+|1&gt;_A|0&gt;_B)<br /> <br />

?
 
Last edited:
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I haven't thought about how to do the Schmidt decomposition of that state vector, but you might find this thread more useful than the one you linked to.
 

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