How to calculate initial velocity and launch angle? (Projectiles)

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SUMMARY

The discussion focuses on calculating the initial velocity and launch angle of a bean bag launched from a height of 0.61m to a corn hole board located 5.18m away, with the back of the board at a height of 0.31m. The bean bag takes 0.900 seconds to reach the board. To solve for the vertical component of the velocity, users are advised to utilize the equation for vertical distance versus time, incorporating the known heights and flight time.

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Homework Statement


A bean bag launcher is used to shoot a bean bag at a corn hole board. The bag is released at a height of .61m above the ground. The front of the board is 5.18m from the location where the launcher releases the bean bag. The back of the board stands .31 m off the ground; the board has a constant slope.

It takes .900 seconds for a bean bag to reach the very back of the board when launched at some initial angle. Given this information, find the original velocity of the bean bag as it is launched, and the angle of launch.

Homework Equations


The Attempt at a Solution

 
Last edited by a moderator:
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Welcome to PF, puppy143158

You have shown know attempt at a solution, which is against the PF rules. You have been warned.

Here is a hint:

- you know the starting and ending heights. Plugging these, along with the flight time, into the equation for vertical distance vs. time should allow you to solve for the vertical component of the velocity.
 

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