Transformation of a Cauchy-Euler equation

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The discussion focuses on transforming a Cauchy-Euler equation given by x²y'' - xy' = ln x. The key step involves substituting x with e^t or t with ln x to facilitate the transformation. Participants emphasize the need to express the derivatives y' and y'' in terms of dy/dt and d²y/dt². Clarification is sought on how to proceed after this substitution. The transformation is crucial for solving the differential equation effectively.
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Homework Statement


x2y'' - xy' = ln x




Homework Equations


The problem I'm having is what do I do with x = et or t = ln x.


The Attempt at a Solution


I know you have to start with x = et or t = ln x however I'm not sure what to do next...
 
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You need to express ## y' = \frac {dy} {dx}, \ y'' = \frac {d^2y} {dx^2} ## in terms of ## \frac {dy} {dt} ## and ## \frac {d^2y} {dt^2} ##.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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