Log Definition and 618 Threads

i don't understand how to find the exact answer to log base 4 64 without using a calculator. can anyone help?my teacher gave examples but they are on bad photocopies sarah

485 + 5 ^ (x + 2) = 12 ^ (2x - 1) This question is driving me nuts. I can't take the log until both sides have been reduced to one expression each, right? If 485 were a power of 5 or 12, then I'd be able to solve it. As it is, I'm clueless. Can someone walk me through the steps to solving for...

Say you have: \frac{\log(x)}{r\log{x}} = y r and y can be any given number. Is there any way to solve this for x? ie \frac{\log(x)}{1.6\log{x}} = 20 I'm getting this because I'm trying to calculate f(x) = \frac{x}{a} where f(x) is of the form f(x) = cx^r a > 1

Can anyone help me with this natural log? ln x + ln(x+1) = 7 I've tried putting it in quadratic form but all I get is x^2 + x - 7=0 which doesn't seem to factor. What am I doing wrong?

Hi, I need to isolet the variabl L from the equation, I'll appreciate any help: G = log [ aL (1-e^(-bL) + S e^(-bL)] I know all the other variables and they are all nombers Thanks, Shira :bugeye:

Please Help! Natural Log Question! Here is the question that is bothering me: I need to solve this natural log for x. Please I need step by step instructions on how to figure out x. Thanks very much. ln (x) + ln (x+1) = 2

-------------------------------------------------------------------------------- Hello, I need help with this problem: 4^x + 4^-x = 5/2 My Solution: (Assume we use log with base 4) log ( 4^x + 4^-x) = log(5/2) = log (4^0) = log (5/2) ? I don't see what I am doing wrong...

Hello, I need help with this problem: 4^x + 4^-x = 5/2 My Solution: (Assume we use log with base 4) log ( 4^x + 4^-x) = log(5/2) = log (4^0) = log (5/2) ? I don't see what I am doing wrong. I used the Product Rule. Any help would be greatly appreciated. Thanks

Here's the problem: find the integral of dx/2x(lnx)^1/2 In other words, dx over 2x times the square root of lnx. It has to be evaluated from 16 and 2. I don't know how to say it, but the integral sign with 16 at the top, and 2 at the bottom. If you can find the answerm and show me...

[SOLVED] Integration of a natural log I am asked to Integrate by parts \int \ln(2x+1) dx So, \mbox{u}=ln(2x+1) \mbox{du}=\frac{2}{2x+1} \mbox{dv}=\mbox{dx} \mbox{v}=\mbox{x} I plug all of that in and I get, {\int \ln(2x+1) dx\}={\mbox{x}\ln(2x+1)}-{\int \frac{2x}{2x+1}...

I have a problem where a graph is drawn, and i am supposed to find the function that would create it. We are only given a part of the graph with certain points. They say it is a log function, and the points given are (0, 0.21), (0.5, 0.19), (1, 0.15), (1.5, 0.10), (1.75, 0). It says to choose a...

Here is the question as it follows: The decibel scale, defined as L = 10 log (\frac{I}{I_0}) where L is the Loudness (or comparative intensity) in decibels (dB), I_0 is the reference level (10^-12 watts per m^2) I is the actual intensity of the sound measured (watts per m^2)...

Does (\log_{x}a - \log_{x}b - \log_{x}c) = \log_{x}(\frac{a}{b/c})?

2^(-log2(x)) It reads, 2 to the power of -log base2 x The problem is that I don't understand why this can also be written as x^-1 For some reason the base and the log2 cancel out. Can anyone explain to me why this happens, please? 1/2^(log2(x)) = 1/x

Hi, I am still having trouble with taking the integral of the following: integral of ln(x+1) dx I am trying to do it by parts but I end up getting stuck. I had no problem doing: integral of ln x dx But I can't seem to get integral of ln (x+1) dx Let u = ln (x+1) then du =...

Hello, It has been over a year since I last took calculus. And I don't recall how to take the integral of a natural logarithmic function. Here is the question that I am supposed to integrate. double integral 1/(x+y) dA where R = [1,2] X [0,1] So what I did first was integrate...

there is a curious 1996 paper by Rovelli that gets the black hole entropy/area formula by a simple counting method. I say simple advisedly---a lot of combinatorics and counting is not really simple at all but IMHO difficult---but in this amazing little 5 page paper the counting of...

I know in Logarithms loga b * logc d = loga d * logc b and loga b * logb c = loga c. Chain Rule. Now I read Calculus, I found out about the Chain rule, are they the same?? Looks like it. But because of my poor English reading, I couldn't understand the text. Can some one explain what...