(0,a) , (b,0) , (2,d) and (e,7) lie on y=2x+1, find a, b, d and e

[Parthyy]

A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.

 

[topsquark]

A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.

You have an equation y = 2x + 1 and several ordered pairs on that line.

So for the first, (0, a) we have
[math]a = 2(0) + 1 = 1[/math]

Thus a =1. Can you finish?

-Dan

 

[HOI]

A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.

Each pair represents (x, y). The line is given as y= 2x+ 1 so (0, a) must satisy a= 2(0)+ 1. similarly, (b, 0) must satisfy 0= 2b+ 1. Solve that equation for b. (2, d) must satisfy d= 2(2)+ 1. (e, 7) must satisfy 7= 2e+ 1. Solve that equation for e.