1350Kg tuned up Civic moving at 15m/s hits a 1450Kg car moving at 12m/s

  • Thread starter Thread starter DrVirus
  • Start date Start date
  • Tags Tags
    Car
Click For Summary
SUMMARY

The discussion focuses on calculating the final velocities of two cars involved in both elastic and inelastic collisions. The first car, a 1350Kg Civic, is moving at 15m/s, while the second car, weighing 1450Kg, is moving at 12m/s. In an elastic collision, both momentum and kinetic energy are conserved, leading to two equations for solving the final velocities. In contrast, for an inelastic collision, only momentum is conserved, and the two cars are assumed to stick together post-collision, simplifying the calculation to a single equation.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Knowledge of kinetic energy conservation in elastic collisions
  • Familiarity with basic physics equations for collisions
  • Ability to manipulate equations with multiple variables
NEXT STEPS
  • Study the equations for elastic collisions, focusing on conservation of momentum and kinetic energy
  • Learn how to solve inelastic collision problems, particularly the concept of objects sticking together
  • Explore real-world applications of collision physics in automotive safety
  • Practice problems involving different mass and velocity combinations in collisions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding collision dynamics in automotive contexts.

DrVirus
Messages
8
Reaction score
0
Im not really good at elastic and inelastic collisions,, can someone help me with collisions please.

In the movie the fast and the furious, a 1350Kg tuned up Civic moving at 15m/s hits a 1450Kg car moving at 12m/s. Determine the final velocity of the cars if (a) the collision was elastic AND (b) the collision was inelastic.

THank you for any help you can give.
 
Last edited by a moderator:
Physics news on Phys.org
DrVirus,
you have 2 unknowns (the final velocities).

In an elastic collision, both momentum and kinetic energy are conserved. So 2 equations, fine.

In an inelastic collision, only momentum is conserved. To get the 2nd equation, you usually assume that the bodies stick together after collision.
 
Well, its been an hour since i posted the question. I got the first part for elastic collision right.. but the inelastic i can't solve it, can someone show me how to solve it, because then tomorrow i have a lab that has to do with collisions and i have to understand this. Thanks a lot
 
As I said:
Momentum: pfinal=pinitial
Sticking: v1,final=v2,final=:vfinal
=>
(m1+m2)vfinal=pinitial

You have calculated pinitial in part (a), haven't you?
 
No, i didnt solve for Pi. i used an equation that works with elastic collision only and has to have V2 as 0. so i change the frame of reference to be 0, and changed it back after i got the answer.
 
pinitial=m1v1,initial+m2v2,initial

Just plug in.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
Replies
4
Views
9K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
7K