Confusion about physics vectors in question

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Homework Help Overview

The discussion revolves around a physics problem involving an inelastic collision between a minivan and a compact car, focusing on the calculation of initial velocities using vector components and trigonometric relationships.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum in two dimensions but encounters confusion regarding the correct use of trigonometric functions for angle calculations. They question why different angles are used in their calculations compared to the textbook.

Discussion Status

Participants are exploring the relationship between sine and cosine functions in the context of the problem. Some have provided clarifications regarding angle relationships, while others have prompted further explanation of the original poster's angle assumptions. There is an acknowledgment of a misunderstanding regarding angle measures, but no consensus on a resolution has been reached.

Contextual Notes

The original poster expresses confusion over the trigonometric relationships used in the problem, particularly regarding the angles derived from the collision scenario. There is a mention of a misinterpretation of angle measures that contributed to the confusion.

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Homework Statement


Engineers perform a crash test with a minivan and a compact car. The mass of the minivan is 800kg and the mass of the compact car is 560kg. The minivan was moving north, and the compact was was moving east.
After the collision, the two cars crumpled together and moved at 15m/s [N 30 E]. Determine the initial velocity of each vehicle

Homework Equations


P = mv

The Attempt at a Solution



Okay so its inelastic:
Minivan is 1
Compact car is 2

x:
m1v1 + m2v2 = mtvf
m2v2 = mtvf
560 * v2 = (560+800)(15*cos70)
v2 = 12.45 m/s [E]

y:
m1v1 + m2v2 = mtvf
800*v2 = (560+800)(15*sin70)
v2 = 24 m/s [N]

The confusion is that these answers are wrong. The book gets completely different answers, and I've discovered its because the book does it like this
How the book is doing it
x:
m1v1 + m2v2 = mtvf
m2v2 = mtvf
560 * v2 = (560+800)(15*sin30)
v2 = 18 m/s [E]

y:
m1v1 + m2v2 = mtvf
800*v2 = (560+800)(15*cos30)
v2 = 22 m/s [N]

This is so confusing for me. Why is the book using sin30 where I use cos70, and why is the book using cos30 where I am using sin70?

I drew the triangle, and I just can't understand why the book is doing it like this. Can someone clear this up? Thanks

I realize this is a trigonometry question. But why isn't sin70 equal to cos30 in the triangle I am drawing? Whats going on?
 
Physics news on Phys.org
sin 70 is equivalent to cos 20 not cos 30

sin 60 is equivalent to cos 30

angles must add to 90 not 100
 
jedishrfu said:
sin 70 is equivalent to cos 20 not cos 30

sin 60 is equivalent to cos 30

angles must add to 90 not 100

Thank you, solves all my problems. I fail at math today. I was thinking 70 + 30 = 90.
 
Perhaps you should first explain where your 70 degree measure came from, if the only angle mentioned in the problem is 30 degree.
 
voko said:
Perhaps you should first explain where your 70 degree measure came from, if the only angle mentioned in the problem is 30 degree.

Everything is solved now, but what I did was I transformed the triangle and set 70 degrees as theta. It should have been 60 degrees, but I wasn't using a calculator so I assumed 90-30 was 70 for some reason
 

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