-2.4.27 find center and radius of circle

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SUMMARY

The discussion centers on determining the center and radius of the circle defined by the equation $x^2+y^2+6x+8y+9=0$. The equation is rewritten and simplified through the method of completing the square, resulting in the standard form $(x+3)^2+(y+4)^2=16$, which reveals the center at C(-3,-4) and a radius R=4. While alternative methods were inquired about, completing the square is confirmed as the most efficient technique for this problem.

PREREQUISITES
  • Understanding of completing the square in algebra
  • Familiarity with the standard form of a circle's equation
  • Basic knowledge of graphing quadratic equations
  • Proficiency in manipulating polynomial expressions
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  • Research the derivation of the standard form of a circle's equation
  • Learn about alternative methods for finding the center and radius of a circle
  • Explore the use of graphing tools like Desmos for visualizing circle equations
  • Study the application of TikZ for creating mathematical graphics in LaTeX
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karush
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Determine the graph of $x^2+y^2+6x+8y+9=0$
$\begin{array}{rll}
\textsf{rewrite} &(x^2+6x )+(y^2+8y)=-9\\
\textsf{complete square} &(x^2+6x+9)+(y^2+8y+16)=-9+9+16\\
\textsf{simplify equation} &(x+3)^2+(y+4)^2=16=4^2\\
\textsf{observation} &C(-3,-4), \quad R=4
\end{array}$

hopefully ok
is there another way to do this other than complete the square

if you are inclined to do so I would be interested in a tikz code would be fore this :unsure:
 
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this is ok

completing the square is probably the most efficient technique ...

Not saying there is no other method, but I'm not familiar with any.
 
Mahalo
often when post here an alternative is suggested...
:cool:
 

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