- #1

karush

Gold Member

MHB

- 3,269

- 5

Find domain asymptotes.

$g(x)=\dfrac{2x^2-14x+24}{x^2+6x-40}$

$\begin{array}{rll}

\textsf{factor}&=\dfrac{2(x-3)(x-4)}{(x-4)(x+10)}

=\dfrac{2(x-3)\cancel{(x-4)}}{\cancel{(x-4)}(x+10)}

=\dfrac{2(x-3)}{x+10}\\

\textsf{Domain} & -\infty<-10<\infty\\

HA \quad y&=3 \\

VA \quad x&=-10

\end{array}$

I think there is an oblique asymptote but ??

Also the OP has a hole at $x=4$ but they didn't ask for it ?

btw how come tab does not work here?