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## Homework Statement

A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18 m/s. The cliff is 52 m above the water's surface. How long does it take for the stone to fall to the water? With what speed does it strike the water?

## Homework Equations

## The Attempt at a Solution

So far, I was able to figure out the time:

dy= 1/2gt^2 where g=9.81 m/s^2

52m= 1/2*9.81*t^2

**t= 3.26 seconds**

I thought it would be correct to use Vy=gt to find the speed at which the stone strikes the water, therefore being (9.81 m/s^2)(3.26 s)= 31.98 m/s. But when i checked the answer key and talked to the teacher, she said that the answer was 36.889 m/s, and I was wrong.

So can someone tell me what I'm doing wrong and how to find the speed at which the stone strikes the water?