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skrelt
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2 Questions -- Heating room air, and fuel combustion efficiency
2 questions. In advance, i needed to translate it so i am sorry if it is states incorrect. I really did my best to do it right.
1.
The density of air at 1 atm and 10.0 ° C is equal to 1.24 kg / m3. (cubic meter)
A room has the following sizes: 8,0 m x 4,5 m x 2,7 m
Calculate how long it takes for a heater of 1.5 kW to heat the air from the room to 21.0 ° C.
Use c = 1005 J / kg / K
2.
An internal combustion engine uses a fuel with calorific value/heating value of 38 MJ / kg.
The density of the fuel is 900 kg / m3. (cubic meter)
Of each MJ heat only 0.25 MJ is converted to mechanical energy.
The efficiency is 25%.
The engine can deliver 30 kW.
Calculate how many liters of fuel per hour the engine used.
http://imgur.com/WQx3BqI
these are the once i used. I probly made some/alot mistakes so i don't know if i need more.
1.
8,0m x 4,5m x 2,7m = 97,2m3 (cubic meters)
1 atm and 10.0 ° C = 1,24 kg/m3
Heater 1,5 kW = 1500 W = 1500 J/s
C = 1005 J/kg/K
This is where I am atm. I figured I needed to change the heater to J/s hence you need to know how long it takes. But after I gathered all the data I could find I don’t know where to start with the calculation or what formula to use first.
2.
Usage = 38 MJ/kg = 0,38 x 10^8 J/kg
P = 900 kg/m3 (cubic meters)
Energy usage = x 0.25
30 kw = 30000 J/s
30000 J/s x 3600 = 1,08 x 10^8 J/hour (first I figured I needed to set it in hours)
0,38x10^8 / 1,08x10^8 = 0,3519 J/kg/hour
900x0,3519 = 316,71 m3 (cubic meters)
316,71 m3 = 316710 dm3 = 316710 Liters of fuel.
I doubt there is an engine that uses that much so I think I made some mistakes.
I hope i can get some help here on 1 or maybe even both questions. Thanks in advance. I tried my best on both and these are the answers and solutions i could produce
Homework Statement
2 questions. In advance, i needed to translate it so i am sorry if it is states incorrect. I really did my best to do it right.
1.
The density of air at 1 atm and 10.0 ° C is equal to 1.24 kg / m3. (cubic meter)
A room has the following sizes: 8,0 m x 4,5 m x 2,7 m
Calculate how long it takes for a heater of 1.5 kW to heat the air from the room to 21.0 ° C.
Use c = 1005 J / kg / K
2.
An internal combustion engine uses a fuel with calorific value/heating value of 38 MJ / kg.
The density of the fuel is 900 kg / m3. (cubic meter)
Of each MJ heat only 0.25 MJ is converted to mechanical energy.
The efficiency is 25%.
The engine can deliver 30 kW.
Calculate how many liters of fuel per hour the engine used.
Homework Equations
http://imgur.com/WQx3BqI
these are the once i used. I probly made some/alot mistakes so i don't know if i need more.
The Attempt at a Solution
1.
8,0m x 4,5m x 2,7m = 97,2m3 (cubic meters)
1 atm and 10.0 ° C = 1,24 kg/m3
Heater 1,5 kW = 1500 W = 1500 J/s
C = 1005 J/kg/K
This is where I am atm. I figured I needed to change the heater to J/s hence you need to know how long it takes. But after I gathered all the data I could find I don’t know where to start with the calculation or what formula to use first.
2.
Usage = 38 MJ/kg = 0,38 x 10^8 J/kg
P = 900 kg/m3 (cubic meters)
Energy usage = x 0.25
30 kw = 30000 J/s
30000 J/s x 3600 = 1,08 x 10^8 J/hour (first I figured I needed to set it in hours)
0,38x10^8 / 1,08x10^8 = 0,3519 J/kg/hour
900x0,3519 = 316,71 m3 (cubic meters)
316,71 m3 = 316710 dm3 = 316710 Liters of fuel.
I doubt there is an engine that uses that much so I think I made some mistakes.
I hope i can get some help here on 1 or maybe even both questions. Thanks in advance. I tried my best on both and these are the answers and solutions i could produce