MHB 231.12.3.19 angle between vectors

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The discussion focuses on finding the angle between the vectors v = -7i - j and w = -i - 7j using the dot product method. The calculation yields a cosine value of approximately 0.28, leading to an angle of about 73.74 degrees. Participants clarify that the cross product is not applicable here since the vectors are in 2D, and the dot product is the correct approach. There is a suggestion to maintain consistent notation throughout the problem for clarity. Overall, the correct angle calculation is confirmed, emphasizing the importance of using appropriate vector notation.
karush
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$\tiny{231.12.3.19}$
$\textsf{Given $v=-7i-j$ and $w=-i-7j$}\\$
$\textsf{find the angle between v and w}\\$
$\displaystyle
\frac{\left(-7, -1, 0\right)\cdot\left(-1, -7, 0\right)}
{\sqrt{50}\cdot \sqrt{50}}
=\frac{14}{50}\approx 0.28$
$\arccos(0.28)\approx 73.74^o$
$\textit{not sure if this is the answer but is cross product also solved with a matrix?}$
 
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Your answer looks good to me.

What are the zeros for? Cross-product is 3-d. What you have here appears to be 2-d and you've used the dot product.
 
I see a lot of vector notation with z=0
thot i would join the club.;)
 
It is best to use the same notation as the problem. I would have written $\frac{(-7i- j)\cdot (-i- 7j)}{\sqrt{50}\sqrt{50}}$
 
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