25 x 25 Grid, find how many shaded squares

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Discussion Overview

The discussion revolves around finding the number of shaded squares in a 25 x 25 grid. Participants explore mathematical approaches, including the use of quadratic formulas and differences, while sharing their understanding and challenges in grasping the concepts involved.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant requests help with a formula to solve the problem easily, stating their answer is 334 squares.
  • Another participant proposes a quadratic formula relating the grid size to a function T(n), suggesting a structure of T(n) = An² + Bn + C.
  • The second difference of the function is noted to be constant (16), indicating a quadratic function, leading to a system of equations to find parameters A, B, and C.
  • It is derived that C = 1, and a simplified system of equations is presented to find A and B, concluding with T(n) = 8n² + 8n + 1.
  • For a 25 x 25 grid, the calculation leads to T(6) = 337, which is presented as the number of shaded squares.
  • A participant expresses gratitude for the explanation and indicates improved understanding of the concept.

Areas of Agreement / Disagreement

There is no consensus on the correct number of shaded squares, as one participant claims 334 while another calculates 337. The discussion includes multiple approaches and interpretations without resolution.

Contextual Notes

The discussion involves assumptions about the grid's structure and the parameters used in the quadratic formula. The derivation steps and the definitions of variables are not fully resolved, leaving some ambiguity in the calculations.

Who May Find This Useful

Participants interested in mathematical problem-solving, particularly in combinatorial geometry and quadratic functions, may find this discussion beneficial.

Marcelo Arevalo
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View attachment 4623

pls help with the formula on solving these the easy way.
It took time for me to find the answer by drawing it literally.
my answer is 334 squares.
 

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I would think this will be a quadratic formula, with the size $s$ of the grid given by:

$$s=4n+1$$ where $n\in\mathbb{N_0}$.

Hence:

$$T(n)=An^2+Bn+C$$

We can count:

$$T(0)=C=1$$

$$T(1)=A+B+C=17$$

$$T(2)=4A+2B+C=49$$

Can you proceed?
 
Hi mark, thanks for replying.
I am a bit lost to the equation you just posted.
Compared to most of the math enthusiast here, I am an amateur. But i really love math.
If you can explain a bit more in an elementary way i will try my very best to follow.
I thank you in advance for being so patient in teaching me.
 
We see that the "second difference" is a constant (16) so we know we are dealing with a quadratic function. And then it's just a matter of using the first 3 values to obtain 3 equations in 3 unknowns (the parameters of the general quadratic).

We see that $C=1$, and so this reduces to the 2X2 system:

$$A+B=16$$

$$2A+B=24$$

From this we find:

$$A=B=8$$

Hence:

$$T(n)=8n^2+8n+1$$

Now, for a 25X25 grid, we have $s=25\implies n=6$ and so we obtain:

$$T(6)=8(6)^2+8(6)+1=337$$
 
thanks a Lot Mark!
Really appreciate it. Now I understand the concept.
 

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