2D Kinematics problem (hill projectile)

1. Jan 19, 2010

1. The problem statement, all variables and given/known data
3. A cannon ball is launched from a cliff with an initial velocity of 50 m/s 300 above the horizontal. If it’s range is 300 m.

a)What is the height of the cliff?
b) What is the impact velocity of the ball right before it strikes the ground?

2. Relevant equations
d=v1t+1/2at^2

d=V*t

Vav=V1+v2/2

3. The attempt at a solution

How do you find the height and impact velocity?
Horizontal: Vx=Cos30*50= 43m/s
dx= 300m

Vertical: Vy=Sin 30*50=25
a= -9.8 m/s^2

I am really stuck!

2. Jan 19, 2010

ideasrule

You need to derive an equation for the range so that you can plug 300m into it. Try writing out the equations of motion for both the x and y directions. Then solve for the x when y=0 (i.e. when the ball hits the ground).

3. Jan 19, 2010

danielatha4

"initial velocity of 50 m/s 300 above the horizontal."

What do you mean by 300 above the horizontal?

4. Jan 19, 2010

sorry i meant 30 degrees

5. Jan 19, 2010

let the height of cliff be h
let the angle be 30 degrees
range = 50cos30 * time = 300
time = 4root3 seconds

initial vertical velocity is vsin30 = 25 m/s
h = 25 - 1/2gt^2
assuming g = 10m/s^2
= - 215 meters
height is 215 meters

impact velocity is easiest calculated using energy conservation
both the equation of motion and energy conservation will lead to the same equation and asnwer
initial energy = 1/2 m 50^2 + mg 215
final energy = 1/2mv^2
v = 84.36 m/s

I don't know if this is right

6. Jan 19, 2010

danielatha4

The time calculated seems right.

h = 25 - 1/2gt^2

I believe your equation is a little bit wrong.

Y = Vot + 1/2gt^2

Does your teacher accept g as 10 m/s^2?? I hate that...

7. Jan 19, 2010

no sorry i was doing this in my head but should i have acceleration as -9.8 m/s with the negative because my velocity is +

How would you do this problem?

8. Jan 19, 2010

danielatha4

I was just pointing out that your Y displacement formula has Vo multiplied by time.

Y = Vot+1/2gt^2

and yea, gravity would be negative.

9. Jan 19, 2010

i just feel very unsure doing this problem and when i do other problems i need to refer to my previous examples, could you give me some tips that you use to solve these easily?
Thanks

10. Jan 19, 2010

danielatha4

Whenever you have a 2-d kinematics problem I always separate into 2 columns all the known data. In the x-direction and in the y-direction. And if you ever need to know something in specifically the x or y axis and it seems as though you have insufficient data, then try linking the two by finding time.

That's just me though. And of course keep in my mind which equations solve for which variables: displacement, initial and final velocity, and time.

11. Jan 19, 2010