1. The problem statement, all variables and given/known data 3. A cannon ball is launched from a cliff with an initial velocity of 50 m/s 300 above the horizontal. If it’s range is 300 m. a)What is the height of the cliff? b) What is the impact velocity of the ball right before it strikes the ground? 2. Relevant equations d=v1t+1/2at^2 d=V*t Vav=V1+v2/2 3. The attempt at a solution How do you find the height and impact velocity? Horizontal: Vx=Cos30*50= 43m/s dx= 300m Vertical: Vy=Sin 30*50=25 a= -9.8 m/s^2 I am really stuck!