2nd order characteristic equation standart form

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SUMMARY

A second order system is represented in standard form as H(s) = K(ω_n²) / (s² + 2ζω_n s + ω_n²) for 0 ≤ ζ ≤ 1. In cases where the system does not conform to this standard, such as H(s) = (s + 1) / (s² + 5s + 3), the numerator's s + 1 term does not directly correspond to the natural frequency ω_n². Instead, the denominator's coefficients must be standardized to identify the damping ratio ζ and natural frequency ω_n. The numerator can be interpreted as Kω_n², where K is a gain factor.

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zoom1
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A second order system has the following standart form;

http://controls-design.com/mathtex/mathtex.cgi?H%28s%29%3DK%5Cfrac%7B%5Comega_n%5E2%7D%7Bs%5E2%2B2%5Czeta%5Comega_n%20s%2B%5Comega_n%5E2%7D%20%5Cmbox%7B%20for%20%7D%200%20%5Cle%20%5Czeta%20%5Cle%201

However, sometimes the system I confront, doesn't hold that equation. I mean something like
s+1/(s^2 + 5s + 3)

At that point, it looks like the s+1 term on the numerator corresponds to Wn^2
But it shouldn't be if I'm not mistaken.

So, what am I supposed to do in such cases, in order to find the let's say damping ratio ?
 
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zoom1 said:
However, sometimes the system I confront, doesn't hold that equation. I mean something like
s+1/(s^2 + 5s + 3)

At that point, it looks like the s+1 term on the numerator corresponds to Wn^2
The numerator has nothing to do with the natural frequency exhibited in the denominator. Once you have standardized the expression to have a unity co-efficient for the denominator's s² term, then the other terms of the denominator give you ζ and Ѡn. The numerator can be thought of as K.Ѡn², where K is a gain factor, a constant, and equals whatever it evaluates as. :smile:
BTW, I believe you are short of a pair of parentheses in your expression; here, borrow a spare pair of mine: ( )[/size][/color]

BTW (2) you didn't get your latex right.http://physicsforums.bernhardtmediall.netdna-cdn.com/images/icons/icon13.gif
 
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