+-2npi OR +-npi How do you know which one to attach?

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SUMMARY

The discussion centers on determining when to use the periodicity of trigonometric functions, specifically in the context of solving equations involving tangent and sine. For the equation tan(4x) = 1, the solution leads to x = π/16 ± nπ, while for sin(x + 2π) + sin(x - 2π) = 1/2, the solution simplifies to sin(x) = 1/4, resulting in arcsin(1/4) = 0.2526 ± 2nπ. The periodicity of the tangent function is π, while sine and cosine functions have a periodicity of 2π.

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Homework Statement



a. tan4x=1

If tanTheta=1, then Theta=pi/4+-npi radians.

4x=pi/4+-npi

x=pi/16+-npi/4

b. sin(x+2pi)+sin(x-2pi)=1/2

sinxcos2pi+cosxsin2pi+sinxcos2pi-sin2picosx=1/2

2sinxcos2pi=1/2

sinxcos2pi=1/4

sinx=1/4

arcsin(1/4)=0.2526+-2npi



Homework Equations


The Attempt at a Solution



So how do you know which one to attach +-npi or +-2npi? I have a slight suspicion that it might be due to periods of trig functions, but I don't trust myself when it comes to math.

Thanks.
 
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What is the period of the tangent function, and what is the period of the sine and the cosine functions?

ehild
 
ehild said:
What is the period of the tangent function, and what is the period of the sine and the cosine functions?

ehild

The tangent function repeats itself every pi and sine cosine functions repeat every 2pi?
 
Yes, correct.

ehild
 
Thank You, Ehild.
 
solve said:
Thank You, Ehild.

You are welcome.

ehild
 

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