- #1

askor

- 169

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Member warned that homework problems must be posted in the Homework sections

How to solve these two absolute value problems?

1.

##|3x - 5| > |x + 2|##

My attempt:

From what I read in my textbook, the closest properties of absolute value is the one that uses "equal" sign

##|3x - 5| = |x + 2|##

##3x - 5 = x + 2##

##3x -x = 5 + 2##

##2x = 7##

##x = \frac{7}{2}##

##|3x - 5| = |x + 2|##

##3x - 5 = -(x + 2)##

##3x - 5 = -x - 2##

##3x + x = 5 - 2##

##4x = 3##

##x = \frac{3}{4}##

However, this absolute uses ">" sign. So, how do you solve this one?

2.

|x - 3| + |2x - 8| = 5

I don't understand at all of absolute value problem like above one. Please help me.

Note: this is the absolute value properties from my textbook (please see attached file).

1.

##|3x - 5| > |x + 2|##

My attempt:

From what I read in my textbook, the closest properties of absolute value is the one that uses "equal" sign

##|3x - 5| = |x + 2|##

##3x - 5 = x + 2##

##3x -x = 5 + 2##

##2x = 7##

##x = \frac{7}{2}##

##|3x - 5| = |x + 2|##

##3x - 5 = -(x + 2)##

##3x - 5 = -x - 2##

##3x + x = 5 - 2##

##4x = 3##

##x = \frac{3}{4}##

However, this absolute uses ">" sign. So, how do you solve this one?

2.

|x - 3| + |2x - 8| = 5

I don't understand at all of absolute value problem like above one. Please help me.

Note: this is the absolute value properties from my textbook (please see attached file).