MHB 3d cube with x,y,z directional vectors

  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    3d Cube Vectors
AI Thread Summary
The discussion centers on plotting a 3D cube with directional vectors in Mathematica, Matlab, or using the TikZ package in LaTeX. Participants clarify that the cube does not require visible x, y, z axes, focusing instead on visualizing the cube in free space with vectors. Several examples using TikZ code are provided, demonstrating how to create the cube and incorporate vectors. The TikZ library is referenced for further details on the XYZ coordinate system, specifically pointing to section 22.2 in the TikZ manual. The conversation emphasizes the need for clear visual representation without axes, showcasing practical code snippets for achieving this in LaTeX.
Dustinsfl
Messages
2,217
Reaction score
5
How can I plot a 3d cube with x,y,z directional vectors going through it?

Mathematica or Matlab or Tikz package Latex
 
Physics news on Phys.org
Do you still need help with this? There are many examples on the web. Do you need the origin to be in the center of the cube or in one of its vertices?
 
Evgeny.Makarov said:
Do you still need help with this? There are many examples on the web. Do you need the origin to be in the center of the cube or in one of its vertices?

I don't need a x,y,z axis. A cube in free space only with vectors. I still need help.
 
This is one way.

Code:
 \usetikzlibrary{arrows}
 \begin{tikzpicture}[>=stealth',x=2cm,y=2cm,z=0.77cm]
 \fill (0,0) circle (1.5pt);
 \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
 \begin{scope}[shift={(0,0,1)}]
 \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
 \end{scope}
 \draw (0,0) -- (0,0,1) (0,1) -- (0,1,1) (1,0) -- (1,0,1) (1,1) -- (1,1,1);
 \end{tikzpicture}

View attachment 362

For the description of the XYZ coordinate system, see section 22.2 on p. 249 in the v. 2.10 TikZ manual.
 

Attachments

  • cube.png
    cube.png
    756 bytes · Views: 104
Evgeny.Makarov said:
This is one way.

Code:
 \usetikzlibrary{arrows}
 \begin{tikzpicture}[>=stealth',x=2cm,y=2cm,z=0.77cm]
 \fill (0,0) circle (1.5pt);
 \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
 \begin{scope}[shift={(0,0,1)}]
 \draw (0,0) -- (1,0) -- (1,1) -- (0,1) -- cycle;
 \end{scope}
 \draw (0,0) -- (0,0,1) (0,1) -- (0,1,1) (1,0) -- (1,0,1) (1,1) -- (1,1,1);
 \end{tikzpicture}

https://www.physicsforums.com/attachments/362

For the description of the XYZ coordinate system, see section 22.2 on p. 249 in the v. 2.10 TikZ manual.

Code:
\begin{tikzpicture}[>=stealth',x = 2cm,y = 2cm,z = 0.77cm]
 \draw[->] (.9,159/110,0)-- (-.5,-107/110,0) node[anchor = south east]{$\frac{\partial }{\partial y}$};
 \draw[->] (-1.3,.15) -- (1.5,.15) node[anchor = north east]{$\frac{\partial }{\partial x}$};
 \draw[->] (.15,-1.3) -- (.15,1.5) node[anchor = north east]{$\frac{\partial }{\partial z}$};
 \draw (-.5,-.5) -- (.5,-.5) -- (.5,.5) -- (-.5,.5) -- cycle;
 \begin{scope}[shift = {(0,0,1)}]
 \draw (-.5,-.5) -- (.5,-.5) -- (.5,.5) -- (-.5,.5) -- cycle;
 \end{scope}
 \draw (-.5,-.5) -- (-.5,-.5,1) (.5,-.5) -- (.5,-.5,1) (.5,.5) -- (.5,.5,1) (-.5,.5) -- (-.5,.5,1);
\end{tikzpicture}
 

Similar threads

Replies
5
Views
2K
Replies
4
Views
2K
Replies
2
Views
3K
Replies
1
Views
2K
Replies
4
Views
2K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
5
Views
2K
Back
Top