5 count bag of balloons, 6 color possibilities

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SUMMARY

The discussion centers on the probability distribution of colors in a 5-count bag of balloons containing 6 different colors. The probability of receiving only one color is calculated as 1 out of 1,296 bags. The probability of receiving all five colors is determined to be 120 out of 1,296 bags. The participants seek to calculate the probabilities for receiving 2, 3, and 4 colors, questioning the relevance of Stirling numbers in these calculations.

PREREQUISITES
  • Understanding of basic probability theory
  • Familiarity with combinatorial mathematics
  • Knowledge of Stirling numbers of the second kind
  • Basic statistical analysis skills
NEXT STEPS
  • Calculate the probability of receiving 2 colors in a 5-count bag of balloons
  • Determine the probability of receiving 3 colors using combinatorial methods
  • Explore the application of Stirling numbers in probability distributions
  • Learn about multinomial distributions for more complex color combinations
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Mathematicians, statisticians, educators, and anyone interested in probability theory and combinatorial analysis.

cad08cad08
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We have a standard assortment of balloons which is 6 different colors. We also have a 5 count bag of balloons which uses this standard assortment. Obviously you can get all 6 colors in a 5 count bag but my colleagues were curious about the other distributions.

The chances of only getting one color is pretty straight forward 1 out of 6^4 or 1 out of 1,296 bags will only have one color. Likewise getting 5 different colors is easy to figure out (1 * 5/6 *4/6 * 3/6 * 2/6) 120 out of 1,296 bags. My question to you is the other possibilities...2, 3, and 4 colors? Does this involve Stirling numbers?

1 color = 1/1,296
2 colors = ?
3 colors = ?
4 colors = ?
5 colors = 120/1,296

Thanks!
 
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cad08cad08 said:
... Obviously you can get all 6 colors in a 5 count bag

Hm ... maybe YOU can but I don't see how.
 
Helpful, thanks.
 

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