5th order DE with g(x)=32exp^(2x)

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SUMMARY

The discussion focuses on solving the fifth-order differential equation y''''' - 4y''' = 32exp^(2x) using the method of variation of parameters. The user successfully derived the homogeneous solution yh(x) = C1 + C2x + C3x^2 + C4exp^(2x) + C5exp^(-2x) and calculated the Wronskian determinant for a 5x5 matrix. The solution involves reducing the equation to a second-order form by letting u = y^{(3)}, leading to the equation u'' - 4u = 32e^{2x}. The user confirmed that integrating u(x) three times yields the general solution for y(x).

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leyyee
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Homework Statement



Use variations of parameters to find the general solutions of the following differential equations.

y'''''-4y'''=32exp^(2x)

Homework Equations



no relevant equations.

The Attempt at a Solution



hey there, I tried solving this question. I got the homogeneous equation.

yh(x)=C1+C2x+C3X2+C4exp^(2x)+C5exp^(-2x)

but after this step.. I am stuck..

Because I am not quite sure whether I am in the correct path to look for the general solutions. After I have this equation, I did the wronskian matrix, I found the determinant of the 5X5 matrix is 512. Am I correct? Please correct me if I am not in the journey to my answer.

Besides that , If I were to use the variations of parameters. The matrix would be 5X5 dimensions. Is it correct?

Thanksedited due to duplication on the template question.. sorry..
 
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You should get into the habit of reducing such a DE into something more familar. Let u=y^{(3)}, so the DE becomes u'' - 4u = 32e^{2x}.

Proceed as usual (involves a 2x2 matrix) to solve for u(x). Then you can obtain y(x).
 
hey there.
thanks a lot for the reply..

i will try out your attempt.. then i will post if i need anymore help..
thanks
 
hey there, i have tried out your attempt.. but I only can find the general solutions

the wronskians i found was -4, am I in the right path ?

u(x) = uh(x) + up(x) = C1e2x+C2e-2x+8xe2x-2e2x

how should I convert it to y(x) = yh(x) + yp(x)

If i use the equation u gave me u = y(3). Am I suppose to integrate u(x) by 3 times?any clue for me?

thanks
 
Last edited:
leyyee said:
hey there, i have tried out your attempt.. but I only can find the general solutions

the wronskians i found was -4, am I in the right path ?

u(x) = uh(x) + up(x) = C1e2x+C2e-2x+8xe2x-2e2x
Well done!

leyyee said:
how should I convert it to y(x) = yh(x) + yp(x)
No need; you've done the variation of parameters work for u.

leyyee said:
If i use the equation u gave me u = y(3). Am I suppose to integrate u(x) by 3 times?
Exactly!
 
Wow.. thanks a lot.. I think I will post the proper solutions after I finished the steps ok ?

and I will let you go through my answer to see whether I did any mistakes.. Thanks
 

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